MySql排除查询

Question

我有一个看起来像这样的表

JOB_ID  | Email        | Type       | Date      
_____________________________________
28319   | mike@aol.com | Service    | 11-24-2016
_____________________________________ 
28412   | mike@aol.com | Rotation   | 11-24-2016
_____________________________________
38123   | andy@aol.com | Service    | 11-24-2016
_____________________________________
28199   | roger@aol.com| Service    | 11-24-2016

我将运行什么查询来返回那些安排了服务但没有在特定日期轮换的人。

这是我的尝试:

SELECT j.Job_ID,j.Email,j.Type,j.Date
from Jobs j 
join
     Jobs  j2
     on j.Email = j2.Customer_Email
where j2.JOB_ID NOT IN (select j.JOB_ID
                  from Jobs j
                  where j.Type = 'Rotation'
                 )     AND j.Date = '11-24-2016';

所以我的查询将返回 andy 和 roger。

Answer 1

这应该可以解决问题，这里不需要连接:

SELECT * FROM Jobs WHERE Date = '11-24-2016' AND Type = 'Service' AND 
Email NOT IN (SELECT Email FROM Jobs WHERE Date = '11-24-2016' AND 
Type = 'Rotation');