我正在尝试开发一个 Android 应用程序，我需要在某个时候将数据插入 MySQL 数据库表('demande')，然后检索新记录的自动递增键(demaynde_id)，为此我使用了 Volley 库，我注意到插入进行得很顺利，但是当涉及到检索 key 时我无法获取它并且出现了这个错误:W/System.err: org.json.JSONException:
类型为 java.lang.String 的值
这是我的php文件
SendingbookingRequest.php
<?php
require("password.php");
$connect = mysqli_connect("localhost", "XXXXXXXX", "XXXXXXX", "XXXXXXXX");
$driver_id = $_POST["driver_id"];
$email = $_POST["email"];
$adresse_source = $_POST["adresse_source"];
$duree = $_POST["duree"];
$distance = $_POST["distance"];
$response = array();
$dt_obj = new DateTime($response['send_moment'], new
DateTimeZone('America/Chicago'));
$dt_obj->setTimezone(new DateTimeZone('Europe/London'));
$send_time = $dt_obj->format('Y-m-d H:i:s');
echo $send_time;
function AddRequest() {
global $connect, $driver_id, $email, $adresse_source, $duree, $distance, $send_time ;
$statement = mysqli_prepare($connect, "INSERT INTO demande (driver_id, pass_id, adresse_source, duree, distance, send_moment) VALUES (?, (SELECT user_id FROM passager WHERE email = ?),?, ?, ?, ?)");
mysqli_stmt_bind_param($statement, "issdis", $driver_id, $email, $adresse_source, $duree, $distance, $send_time);
mysqli_stmt_execute($statement);
}
function getDemandeId() {
global $connect,$driver_id, $email;
$statement = mysqli_prepare($connect, "SELECT LAST_INSERT_ID() FROM demande WHERE driver_id = ? AND pass_id = (SELECT user_id FROM passager WHERE email = ?)");
mysqli_stmt_bind_param($statement,"is", $driver_id, $email);
mysqli_stmt_execute($statement);
mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statement, $demande_id);
while(mysqli_stmt_fetch($statement)){
$response["demande_id"] = $demande_id;
}
}
$response["success"] = false;
AddRequest();
getDemandeId();
$response["success"] = true;
echo json_encode($response);
?>
我尝试删除 getDemandeId()，插入成功，但我在 Android Studio 中遇到了同样的错误。
最佳答案
您检查过回复了吗？格式是否正确 尝试记录您收到的响应并查看其格式是否正确。 当您尝试将字符串转换为格式不正确的 jsonObject 时会发生此异常
关于php - 使用 Volley 插入后无法自动递增，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/43572164/