php - undefined variable

Question

所以我在我的登录页面上遇到了这个问题，它无法找到我设置的变量，但我已经确定它在数据库中。我已经将它与数据库进行了比较，它似乎都匹配，所以我不确定为什么我会收到此错误。请在下面找到详细信息。感谢您的帮助:)

Error : Notice: Undefined variable: ID in /home/scylla97/public_html/login.php on line 89

代码:

            $SQLCheckLogin = $odb -> prepare("SELECT COUNT(*) FROM `users` WHERE `username` = :username AND `password` = :password");
        $SQLCheckLogin -> execute(array(':username' => $username, ':password' => SHA1($password)));
        $countLogin = $SQLCheckLogin -> fetchColumn(0);
        if ($countLogin == 1)
        {
            $SQLGetInfo = $odb -> prepare("SELECT `access`, `username`, `ID`, `rank` FROM `users` WHERE `username` = :username AND `password` = :password");
            $SQLGetInfo -> execute(array(':username' => $username, ':password' => SHA1($password)));
            $userInfo = $SQLGetInfo -> fetch(PDO::FETCH_ASSOC);
            if ($userInfo['access'] == 0)
            {
                $_SESSION['username'] = $userInfo['username'];
                $_SESSION['ID'] = $userInfo['ID'];
                {
                    $ip = getRealIpAddr();
                    if (filter_var($ip, FILTER_VALIDATE_IP))
                    {
                        $SQL = $odb -> prepare('INSERT INTO `logs` VALUES(:id ,:username, :loggedip, UNIX_TIMESTAMP())');
                        $SQL -> execute(array(':loggedip' => $ip, ':username' => $username, ':id' => $id));
                        echo '<div class="nNote nSuccess hideit"><p><font color=\'white\'><strong>SUCCESS: </strong>Login Successful. Redirecting....</font></p></div><meta http-equiv="refresh" content="3;url=index.php">';
                        die();

第 89 行是:

$SQL -> execute(array(':loggedip' => $ip, ':username' => $username, ':id' => $id));

日志数据库:

如果这是一个愚蠢的问题并且真的很容易解决，我深表歉意，但我花了最后几个小时查看并尝试它但仍然没有解决。

Answer 1

你错过了你的 $id 值并希望你的 $username 已经得到所以首先使用 $id 赋值

$id = $userInfo['ID'];

所以添加这一行

$_SESSION['username'] = $userInfo['username'];
$_SESSION['ID'] = $userInfo['ID'];
$id = $userInfo['ID'];

所以你的查询

 $SQL -> execute(array(':loggedip' => $ip, ':username' => $username, ':id' => $id));

或更新您的查询

$SQL -> execute(array(':loggedip' => $ip, ':username' => $username, ':id' => $_SESSION['ID']));

希望对你有帮助