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我必须从一个表中获取每周报告,其中每条记录都有它们的状态,例如 1 表示打开,2 表示关闭,所以我将周作为一个按键分组,并使用案例条件来计算差异计数,例如打开、关闭、红色等等,但数据并不像我想要的那样准确。 您将更好地理解下面提到的查询。 每一个回应都是适当的。
SELECT DISTINCT discussion_date,department,DAYNAME(discussion_date) AS DAY,CONCAT(YEAR(discussion_date),'/',WEEK(discussion_date)) AS week_name,YEAR(discussion_date) AS YEAR,CONCAT('WEEK -', WEEK(discussion_date)) AS week_no,COUNT(*) as total_queries,(CASE WHEN review_items.status = 1 AND due_date > curdate() THEN count(*) ELSE 0 END) as open,(CASE WHENreview_items.status = 2 THEN count(*) ELSE 0 END) as closed,(case when manager_closuredate > due_date THEN count(*) ELSE 0 END) as red,(CASE WHEN review_items.status = 3 THEN count(*) ELSE 0 END) as hold,(CASE WHEN review_items.status = 4 THEN count(*) ELSE 0 END) as discussion,DATE_ADD(discussion_date,INTERVAL(2 - DAYOFWEEK(discussion_date)) DAY) AS Week_start_date,DATE_ADD(discussion_date,INTERVAL(7 - DAYOFWEEK(discussion_date)) DAY) AS Week_end_date,DAYNAME(DATE_ADD(discussion_date,INTERVAL(2 - DAYOFWEEK(discussion_date)) DAY)) AS WeeK_Start_DAY FROM review_items
WHERE department = 'Development' AND discussion_date BETWEEN '2017-08-01' AND '2017-08-31'
GROUP BY week_name
ORDER BY YEAR (discussion_date) ASC,WEEK(discussion_date) ASC