php - 电子邮件字段未保存到数据库 - Android 注册页面

Question

我想了解如何在服务器数据库上保存用户详细信息。 虽然通过观看视频并按照上述步骤操作，我能够保存名称、密码、出生日期，但电子邮件字段每次都显示 0。请告诉我问题出在哪里，我无法理解。以下是我的代码。

注册.php

<?php
$con = mysqli_connect("my_host", "db_user", "db_password", "my_db");
$name = $_POST["name"];
$email = $_POST["email"];
$password = $_POST["password"];
$dob = $_POST["dob"];
$statement = mysqli_prepare($con, "INSERT INTO user (name, email, password, dob) VALUES (?, ?, ?, ?)");
mysqli_stmt_bind_param($statement, "siss", $name, $email, $password, $dob);
mysqli_stmt_execute($statement);
$response = array();
$response["success"] = true;  
echo json_encode($response);
?>

为此我正在使用 Volley。

注册请求类

public class RegisterRequest extends StringRequest {

private static final String REQUEST_REGISTER_URL = "http://www.myhostingaddress/register.php";
private Map<String, String> params;

public RegisterRequest(String name, String email, String password, String dob, Response.Listener<String> listener){
    super(Method.POST, REQUEST_REGISTER_URL,listener,null);
    params = new HashMap<>();
    params.put("name", name);
    params.put("email", email);
    params.put("password", password);
    params.put("dob",dob);
}

@Override
public Map<String, String> getParams() {
    return params;
}
}

和我的主要注册 Activity

注册类

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_sign_up);

    name = (EditText) findViewById(R.id.name);
    eemail = (EditText) findViewById(R.id.email);
    password = (EditText) findViewById(R.id.password_signup);
    dob = (EditText) findViewById(R.id.DOB);
    register_btn = (Button) findViewById(R.id.Signup);

    register_btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            final String Name = name.getText().toString();
            final String Email = eemail.getText().toString();
            final String Password = password.getText().toString();
            final String Dob = dob.getText().toString();


            Response.Listener<String> responseListener = new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    try {
                        JSONObject jsonResponse = new JSONObject(response);
                        boolean success = jsonResponse.getBoolean("success");

                        if (success){
                            Toast.makeText(Sign_up.this, "Account Created, Login now !", Toast.LENGTH_SHORT).show();
                            startActivity(new Intent(Sign_up.this,Login_Page.class));
                        } else {
                            Toast.makeText(Sign_up.this, "Registration Failed, Try Again !", Toast.LENGTH_SHORT).show();
                        }

                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            };

            RegisterRequest registerRequest = new RegisterRequest(Name,Email,Password,Dob,responseListener);
            RequestQueue queue = Volley.newRequestQueue(Sign_up.this);
            queue.add(registerRequest);
        }
    });
}
}

Answer 1

这里的答案很简单，您使用 i(整数)而不是 s(字符串)作为 email bind_param() 的参数。我真诚地怀疑那是一个整数。

您还最好确保 email 列的类型确实是可以存储字符串的类型。

因此，将所有字符串的 siss 更改为 ssss。