这是我名为 Class 的实体:
package az.bank.entities;
import java.io.Serializable;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table (name = "cards")
public class Card implements Serializable{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String cardHolder;
private String cardNumber;
private String cardPassword;
private String expiryYear;
private String expiryMonth;
private String cardType;
private double cardBalance;
}
这是我的 persistance.xml 文件:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="BankServicePU" transaction-type="JTA">
<jta-data-source>jdbc/BankService</jta-data-source>
<class>az.bank.entities.Card</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/cards" />
<property name="javax.persistence.jdbc.user" value="root" />
<property name="javax.persistence.jdbc.password" value="root" />
<property name="javax.persistence.schema-generation.database.action" value="create"/>
</properties>
</persistence-unit>
</persistence>
我已经创建了名为 jdbc/BankService 的连接池和名为 cards 的 mySQL 方案。但是当我部署和运行程序时，它不会在该方案中创建表。请帮助我在这里做错了什么。
最佳答案
如果您的数据库已经包含卡片表，那么先删除它。使用
<property name="javax.persistence.schema-generation.database.action" value="drop-and-create"/>
关于java - 当我运行程序时，JPA 不会在 MySQL 中创建表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/46618802/