我的代码以列表形式输出
def extractKeywords():
<code>
return list
list = []
data = extractKeywords()
for x in range(0,5):
get = data[0][x]
list.append(get)
print list12
输出列表为
['LION', 'tv', 'TIGER', 'keyboard', 'cd-writer','ELEPHANT']
我如何将此列表分为两组，例如(预期输出)
Animals = ['LION', 'TIGER', 'ELEPHANT']
Electronics = ['tv', 'keyboard', 'cd-writer']
所有动物均采用大写字母，电子产品均采用小写字母
最佳答案
此解决方案使用 itertools.groupby 来避免遍历列表两次。
>>> from itertools import groupby
>>> data = ['LION', 'tv', 'TIGER', 'keyboard', 'cd-writer','ELEPHANT']
>>> # upper case letters have lower `ord` values than lower case letters
>>> sort_by_case = sorted(data, key=lambda word: ord(word[0]))
>>> sort_by_case
['ELEPHANT', 'LION', 'TIGER', 'cd-writer', 'keyboard', 'tv']
>>> # group the words according to whether their first letter is upper case or not
>>> group_by_case = groupby(sort_by_case, lambda word: word[0].isupper())
>>> # use tuple unpacking to assign the two groups to appropriate variables
>>> upper_case, lower_case = [list(g) for (k, g) in group_by_case]
>>> upper_case
['ELEPHANT', 'LION', 'TIGER']
>>> lower_case
['cd-writer', 'keyboard', 'tv']
关于python - 根据类别对列表进行分组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19559708/