python - Django admin，只显示需要的模型

Question

我是 django 的新手，我只需要在管理中显示那些状态为“待处理”的模型。

ITEM_STATUSES = (
    ('pending', _('Waiting approval')),
    ('approved', _('Approved')),
    ('declined', _('Declined'))
)

class Item(models.Model):
    title = models.CharField(max_length=64)
    ...
    status = models.CharField(max_length=32, choices=ITEM_STATUSES)
    ...

class ItemAdmin(admin.ModelAdmin):
  pass

admin.site.register(Item, ItemAdmin)

Answer 1

覆盖 get_queryset() (对于 django>=1.6)你的 ModelAdmin 方法:

The get_queryset method on a ModelAdmin returns a QuerySet of all model instances that can be edited by the admin site.

class ItemAdmin(admin.ModelAdmin):
    def get_queryset(self, request):
        qs = super(ItemAdmin, self).get_queryset(request)
        return qs.filter(status='pending')

仅供引用，对于 django <= 1.5 使用 queryset()方法代替。