我使用 Barriers 在 Python3 中实现了这段代码。我想在 Python2.7 中获得相同的功能,但我不知道要使用哪个同步原语,因为 Barriers 在 Python2.7 中不存在
import threading
import time
from threading import Thread,Barrier
b = Barrier(2, timeout=50)
def func1():
time.sleep(3)
b.wait()
print('Working from func1')
return
def func2():
time.sleep(5)
b.wait()
print('Working from func2')
return
if __name__ == '__main__':
Thread(target = func1).start()
Thread(target = func2).start()
最佳答案
您可以使用信号量模拟屏障。 看一眼: Implementing an N process barrier using semaphores
问题是它没有超时参数,可能使用了Conditions ...
import time
from threading import Thread,Semaphore
class Barrier:
def __init__(self, n):
self.n = n
self.count = 0
self.mutex = Semaphore(1)
self.barrier = Semaphore(0)
def wait(self):
self.mutex.acquire()
self.count = self.count + 1
self.mutex.release()
if self.count == self.n: self.barrier.release()
self.barrier.acquire()
self.barrier.release()
b = Barrier(2)
def func1():
time.sleep(3)
#
b.wait()
#
print('Working from func1')
return
def func2():
time.sleep(5)
#
b.wait()
#
print('Working from func2')
return
if __name__ == '__main__':
Thread(target = func1).start()
Thread(target = func2).start()
关于python - 在Python2.7中实现Barrier,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26622745/