我希望在 python 中创建以下列表:
list = ["pix420_615", "pix421_615", ... , "pix425_620"]
注意其中列表是字符串列表，而不是值。
来自以下两个列表:
x= [420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425,
420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425]
y= [615, 615, 615, 615, 615, 615, 616, 616, 616, 616, 616, 616, 617, 617, 617, 617, 617, 617,
618, 618, 618, 618, 618, 618, 619, 619, 619, 619, 619, 619, 620, 620, 620, 620, 620, 620]
我想知道我将如何着手这样做，并保持相应数组值的一致性......？
最佳答案
这应该可以解决问题。 zip 是执行此类操作的最佳方式:
x = [420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425, 420, 421, 422, 423, 424, 425]
y = [615, 615, 615, 615, 615, 615, 616, 616, 616, 616, 616, 616, 617, 617, 617, 617, 617, 617, 618, 618, 618, 618, 618, 618, 619, 619, 619, 619, 619, 619, 620, 620, 620, 620, 620, 620]
z = ['pix{}_{}'.format(a, b) for a, b in zip(x, y)]
print(z)
# Output:
# ['pix420_615', 'pix421_615', 'pix422_615', 'pix423_615', 'pix424_615', 'pix425_615', 'pix420_616', 'pix421_616', 'pix422_616', 'pix423_616', 'pix424_616', 'pix425_616', 'pix420_617', 'pix421_617', 'pix422_617', 'pix423_617', 'pix424_617', 'pix425_617', 'pix420_618', 'pix421_618', 'pix422_618', 'pix423_618', 'pix424_618', 'pix425_618', 'pix420_619', 'pix421_619', 'pix422_619', 'pix423_619', 'pix424_619', 'pix425_619', 'pix420_620', 'pix421_620', 'pix422_620', 'pix423_620', 'pix424_620', 'pix425_620']
关于python - 如何从两个 "array.flatten()"-ed列表在python中创建字符串列表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/38379679/