我想根据换行符拆分字符串并将新行替换为“.”在 python 。我试过这段代码，但我不明白。
import nltk
from nltk.tokenize.punkt import PunktSentenceTokenizer, PunktParameters, PunktLanguageVars
ex_sent="Conclusion & Future Work
In our project we have tried for implementing northbound SDN application for OpenFlow protocol evaluation. The client and the RYU application is being connected, via socket connection."
class CommaPoint(PunktLanguageVars):
sent_end_chars = (',','\n')
tokenizer = PunktSentenceTokenizer(lang_vars = CommaPoint())
sentences = sentence_splitter.tokenize(ex_sent)
print sentences
最佳答案
换行符是\n。所以如果你想用 . 替换字符串中的所有新行字符，你应该使用 replace() 方法。在这种情况下:
your_string.replace('\n', '.')
第二种方法是 .split('\n') 按换行符然后 '.'.join(your_string)。你应该检查 Python documentation.
关于python - 如何从python中的字符串中搜索换行符，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39345915/