如何从字典中的键设置 xticks?在我的原始代码中,字典是空的,并根据数据文件进行填充,因此我不能为 xticks 设置任何静态内容。根据用户输入的内容(1-10 之间的数字),该图从该数量的最高值到最低值绘制,但我希望用户能够看到该值属于哪个 IP。键是 IP 地址,因此刻度线也必须是垂直的,因为它们会占用相当大的空间。谢谢
from collections import Counter
import matplotlib.pyplot as plt
import numpy as np
frequency2 = Counter({'205.166.231.2': 10, '205.166.231.250': 7, '205.166.231.4': 4, '98.23.108.3': 2, '205.166.231.36': 1})
vals = sorted(frequency2.values(), reverse=True)
response2 = int(input("How many top domains from source? Enter a number between 1-10: "))
if response2 > 0 and response2 < len(vals)+1:
figure(1)
y = vals[:response2]
print ("\nTop %i most domains are:" %response2)
for key, frequency2_value in frequency2.most_common(response2):
print("\nDomain IP:",key,"with frequency:",frequency2_value)
x = np.arange(1,len(y)+1,1)
fig, ax = plt.subplots()
ax.bar(x,y,align='center', width=0.2, color = 'g')
ax.set_xticks(x)
ax.set_xlabel("This graph shows amount of protocols used")
ax.set_ylabel("Number of times used")
ax.grid('on')
else:
print ("\nThere are not enough domains for this top amount.")
最佳答案
根据您的示例正确设置 x 轴上的标签有两个步骤。您必须从字典中获取正确的键,然后必须将它们设置为轴标签(并旋转它们以便它们清晰可见)。
1) 获取正确的标签
标签是字典的键。问题是字典中的键没有排序,您需要它们的顺序与排序后的值相同。
获取 dictionary keys sorted by the values可以通过多种方式完成,但在您的代码中,您已经在 for
循环中以正确的顺序遍历键。添加一个新的列表变量来存储这样的键:
x_labels = [] #create an empty list to store the labels
for key, frequency2_value in frequency2.most_common(response2):
print("\nDomain IP:",key,"with frequency:",frequency2_value)
x_labels.append(key) #store each label in the correct order (from .most_common())
现在 x_labels
列表以正确的顺序包含您想要的标签。
2) 设置xtick标签
设置标签需要调用 ax.set_xticklabels()
使用 ax.set_xticks()
设置 x 刻度位置后。您还可以在调用 ax.set_xticklabels()
时指定标签的旋转。此处显示添加的行:
ax.bar(x, y, align='center', width=0.2, color = 'g')
ax.set_xticks(x)
ax.set_xticklabels(x_labels, rotation=90) #set the labels and rotate them 90 deg.
关于python - 如何根据字典中的键设置 Xticks,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43578055/