我正在学习中级Python。
假设有一个字符串
astring = '[Embodied cognition - Wikipedia](https://en.wikipedia.org/wiki/Embodied_cognition)'
使用string.punctuation提取单词
from string import punctuation
for delimiter in punctuation:
if delimiter in astring:
astring = astring.replace(delimiter, ' ')
In [7]: astring
Out[7]: ' Embodied cognition Wikipedia https en wikipedia org wiki Embodied cognition '
我尝试使用map并且它有效
In [12]: a = map(astring.replace, punctuation, ' ')
In [14]: list(a)
Out[14]: [' Embodied cognition Wikipedia https en wikipedia org wiki Embodied cognition ']
如何用其他先进技术解决该问题？
最佳答案
您应该研究一下正则表达式(简称 regex)。
import re
astring = '[Embodied cognition - Wikipedia](https://en.wikipedia.org/wiki/Embodied_cognition)'
re.sub(r'[^A-Za-z0-9]+', ' ', astring)
# returns:
' Embodied cognition Wikipedia https en wikipedia org wiki Embodied cognition '
关于python - 替换字符串中的多个元素，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/47523313/