我编写了这个脚本,它创建向左移动并停在某个点的灰色方 block ,并创建无限向右移动的红色方 block 。目前每个方 block 只能制作 1 个。
在我看来(我是初学者)下面的脚本部分是循环的,因此每次计算机执行循环时,它都应该创建一个新的灰色方 block ,直到总共有 15 个方 block 。为什么不呢?
(顺便说一句,德国人是灰色方 block )
if germancount<15:
spawn_soldier(german_startx, german_starty, german_width, german_height, grey)
我的完整代码如下:
import pygame
import time
import random
pygame.init()
display_width = 1000
display_height= 800
black = (0,0,0)
white = (255,255,255)
red = (255,0,0)
green = (0,255,0)
blue = (0,0,255)
grey=(169,169,169)
gameDisplay= pygame.display.set_mode((800,600))
pygame.display.set_caption('stalingrad')
clock = pygame.time.Clock()
def spawn_soldier(thingx,thingy, thingw, thingh, colour):
pygame.draw.rect(gameDisplay, colour,[thingx, thingy, thingw, thingh])
def game_loop():
russian_width= 20
russian_height= 20
russian_speed = 2
russian_startx=-30
russian_starty=random.randrange(0, display_height)
german_width=20
german_height=20
german_speed=-1
german_startx=780
german_starty=random.randrange(0, display_height)
germancount=0
russiancount=0
game_exit=False
while not game_exit:
gameDisplay.fill(white)
if germancount<15:
spawn_soldier(german_startx, german_starty, german_width, german_height, grey)
if german_startx > 700:
german_startx += german_speed
if russiancount<100:
spawn_soldier(russian_startx, russian_starty, russian_width, russian_height, red)
russian_startx += russian_speed
pygame.display.update()
clock.tick(60)
game_loop()
pygame.quit()
quit()
编辑,我想我找到了一种更好地定义我的问题的方法。
我需要大约 15 个这样的“spawn_soldier”函数,仅供德国人使用。
spawn_soldier_1(german_startx, german_starty, german_width,
spawn_soldier_2(german_startx, german_starty, german_width,
spawn_soldier_3(german_startx, german_starty, german_width,
有没有办法让它用不同的 y 值执行该函数的 115 个不同版本,而无需复制和粘贴 115 次?因为那将是一场噩梦。
最佳答案
每次循环时,您都会生成一名新士兵。事实上,因为您从不更改 germancount
或 Russiancount
,所以您不仅会这样做 15 次,而且会永远这样做。每次,你都会用白色覆盖所有现有的士兵,然后永远产生一个新的德国人和一个新的俄罗斯人(尽管最终他们会离开屏幕边缘,所以你不会看到他们)。
我认为你想要的是编写一个绘制士兵的函数:
def draw_soldier(rect, colour):
pygame.draw.rect(gameDisplay, colour, rect)
然后,在帧循环内,像斯大林格勒的冬天一样,用一片白雪删除整个屏幕后,每次添加一个新的矩形,然后重新绘制所有矩形:
# When the game starts, there are no soldiers
germans = []
russians = []
while not game_exit:
gameDisplay.fill(white)
# Each time through the loop, add another soldier to each
# side until they're full
if len(germans) < germancount:
germans.append([german_startx, german_starty, german_width, german_height])
german_startx += german_speed
if len(russians) < russiancount:
russians.append([russian_startx, russian_starty, russian_width, russian_height])
russian_startx += russian_speed
# Now draw all the soldiers in front of that white fill
for german in germans:
draw_soldier(german, grey)
for russian in russians:
draw_soldier(russian, red)
pygame.display.update()
clock.tick(60)
关于python - 为什么Python每次循环时不执行一个函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51886457/