c# - 反射 - 获取属性名称

Question

<分区>

Answer 1

这可以使用表达式来实现:

// requires object instance, but you can skip specifying T
static string GetPropertyName<T>(Expression<Func<T>> exp)
{
    return (((MemberExpression)(exp.Body)).Member).Name;
}

// requires explicit specification of both object type and property type
static string GetPropertyName<TObject, TResult>(Expression<Func<TObject, TResult>> exp)
{
    // extract property name
    return (((MemberExpression)(exp.Body)).Member).Name;
}

// requires explicit specification of object type
static string GetPropertyName<TObject>(Expression<Func<TObject, object>> exp)
{
    var body = exp.Body;
    var convertExpression = body as UnaryExpression;
    if(convertExpression != null)
    {
        if(convertExpression.NodeType != ExpressionType.Convert)
        {
            throw new ArgumentException("Invalid property expression.", "exp");
        }
        body = convertExpression.Operand;
    }
    return ((MemberExpression)body).Member.Name;
}

用法:

var x = new ObjectType();
// note that in this case we don't need to specify types of x and Property1
var propName1 = GetPropertyName(() => x.Property1);
// assumes Property2 is an int property
var propName2 = GetPropertyName<ObjectType, int>(y => y.Property2);
// requires only object type
var propName3 = GetPropertyName<ObjectType>(y => y.Property3);

更新:已修复 GetPropertyName<TObject>(Expression<Func<TObject, object>> exp)对于返回值类型的属性。