python - 使用 Python 和 BeautifulSoup，仅选择未包含在 <a> 中的文本节点

Question

我正在尝试解析一些文本，以便我可以对未格式化的链接进行 URL 化(用标签包装)。以下是一些示例文本:

text = '<p>This is a <a href="https://google.com">link</a>, this is also a link where the text is the same as the link: <a href="https://google.com">https://google.com</a>, and this is a link too but not formatted: https://google.com</p>'

这是我迄今为止从 here 得到的内容:

from django.utils.html import urlize
from bs4 import BeautifulSoup

...

def urlize_html(text):

    soup = BeautifulSoup(text, "html.parser")

    textNodes = soup.findAll(text=True)
    for textNode in textNodes:
        urlizedText = urlize(textNode)
        textNode.replaceWith(urlizedText)

    return = str(soup)

但这也会捕获示例中的中间链接，导致其双重包裹在 <a> 中标签。结果是这样的:

<p>This is a <a href="https://djangosnippets.org/snippets/2072/" target="_blank">link</a>, this is also a link where the test is the same as the link: <a href="https://djangosnippets.org/snippets/2072/" target="_blank">&lt;a href="https://djangosnippets.org/snippets/2072/"&gt;https://djangosnippets.org/snippets/2072/&lt;/a&gt;</a>, and this is a link too but not formatted: &lt;a href="https://djangosnippets.org/snippets/2072/"&gt;https://djangosnippets.org/snippets/2072/&lt;/a&gt;</p>

我可以对 textNodes = soup.findAll(text=True) 做什么？这样它只包含尚未包含在 <a> 中的文本节点标签？

Answer 1

文本节点保留其parent引用，因此您可以只测试a标签:

for textNode in textNodes:
    if textNode.parent and getattr(textNode.parent, 'name') == 'a':
        continue  # skip links
    urlizedText = urlize(textNode)
    textNode.replaceWith(urlizedText)