python - 根据字典中的键对在数据框中创建不同的列

Question

这是我创建的字典的一部分:

defaultdict (int,
         {"['por', 'rus']": 80,
         "['nld', 'slv']": 4,
         "['jpn', 'pol']": 48,
         "['ces', 'epo']": 4,
         "['oci', 'ron']": 4,
         "['lit', 'mkd']": 2,
         "['deu', 'ewe']": 2,
         "['cat', 'ron']": 4,
         "['ces', 'ita']": 18,
         "['est', 'fra']": 14,
         "['hin', 'mal']": 4,

我想要 3 列，column1:第一个键，column2:第二个键，column3:值。

当我创建数据框时:

pairs_df = pd.DataFrame(list(pairs.iteritems()), columns = ['column1','column2'])
pairs_df.head()

输出:

           column1  column2
0   ['por', 'rus']       80
1   ['est', 'fra']       14
2   ['nld', 'slv']        4
3   ['jpn', 'pol']       48
4   ['ces', 'epo']        4
5   ['hin', 'mal']        4
6   ['oci', 'ron']        4
7   ['lit', 'mkd']        2
8   ['deu', 'ewe']        2
9   ['cat', 'ron']        4
10  ['ces', 'ita']       18

键进入一列，但我无法设法将它们分成树列。

Answer 1

这是你想要的吗？

import re

mydict=  {"['por', 'rus']": 80,
         "['nld', 'slv']": 4,
         "['jpn', 'pol']": 48,
         "['ces', 'epo']": 4,
         "['oci', 'ron']": 4,
         "['lit', 'mkd']": 2,
         "['deu', 'ewe']": 2,
         "['cat', 'ron']": 4,
         "['ces', 'ita']": 18,
         "['est', 'fra']": 14,
         "['hin', 'mal']": 4}


# this is where you seem to be stuck
for k,v in mydict.iteritems():
    print k,v    # keys are still strings, not lists

# this is the resolution, separation of the keys into two strings    
for k,v in mydict.iteritems():
    a=re.findall('\w{3}',k) 
    print a[0],a[1],v

输出:

['por', 'rus'] 80
['nld', 'slv'] 4
['jpn', 'pol'] 48
['ces', 'epo'] 4
['oci', 'ron'] 4
['lit', 'mkd'] 2
['deu', 'ewe'] 2
['cat', 'ron'] 4
['ces', 'ita'] 18
['est', 'fra'] 14
['hin', 'mal'] 4
por rus 80
nld slv 4
jpn pol 48
ces epo 4
oci ron 4
lit mkd 2
deu ewe 2
cat ron 4
ces ita 18
est fra 14
hin mal 4

现在，如果您愿意，您可以将它们附加到列表中:

 x,y,z=[],[],[]
    for k,v in mydict.iteritems():
        a=re.findall('\w{3}',k) 
        x.append(a[0])
        y.append(a[1])
        z.append(v)
print x,y,z

或者如果你喜欢 pandas Dataframe:

import pandas as pd
df = pd.DataFrame({'a': x, 'b': y,'c':z})
print df

输出:

['por', 'nld', 'jpn', 'ces', 'oci', 'lit', 'deu', 'cat', 'ces', 'est', 'hin'] ['rus', 'slv', 'pol', 'epo', 'ron', 'mkd', 'ewe', 'ron', 'ita', 'fra', 'mal'] [80, 4, 48, 4, 4, 2, 2, 4, 18, 14, 4]
      a    b   c
0   por  rus  80
1   nld  slv   4
2   jpn  pol  48
3   ces  epo   4
4   oci  ron   4
5   lit  mkd   2
6   deu  ewe   2
7   cat  ron   4
8   ces  ita  18
9   est  fra  14
10  hin  mal   4