python - 在所有不符合条件的行上过滤 Pandas 数据框

Question

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Answer 1

由于 numpy(因此 pandas)使用按位运算符，您应该将 not 替换为 ~。这也是您使用 & 而不是 and 的原因。

import pandas as pd

df = pd.DataFrame({'a': [1, 2]})

print(df[~(df['a'] == 1)])
>>    a
   1  2

并使用您的示例:

import pandas as pd
import numpy as np

df = pd.DataFrame([[5,7, 'wolf'],
              [5,6,'cow'],
              [8, 2, 'rabbit'],
              [5, 3, 'rabbit'],
              [3, 2, 'cow'],
              [7, 5, 'rabbit']],
              columns = ['lat', 'long', 'type'])

coords = [5,7] #the coordinate I'm testing, a wolf

view = df[((coords[0] - 1) <= df['lat']) & (df['lat'] <= (coords[0] + 1)) \
    & ((coords[1] - 1) <= df['long']) & (df['long'] <= (coords[1] + 1))]

view = view[~ ((coords[0] == view['lat']) & (coords[1] == view['long'])) ] 

print(view)
>>    lat  long type
   1    5     6  cow