当python只需要文件夹时，python打印文件夹和子文件夹

Question

我正在制作一个程序，用 python 打印 90 天内的所有文件夹。
这是我的代码:

import os
from datetime import date
from Tkinter import *
import Tkinter, Tkconstants, tkFileDialog


old_dirs = []
today = date.today()

home1 = os.path.join(os.environ["HOMEPATH"], "Desktop")
desktop = os.path.join(os.path.join(os.environ['USERPROFILE']), 'Desktop')

root = Tk()
root.withdraw()
path = tkFileDialog.askdirectory(initialdir=desktop, title="Select folder to 
scan from: ")
path = path.encode('utf-8')

for root, dirs, files in os.walk(path):
    for name in dirs:
        filedate = date.fromtimestamp(os.path.getmtime(os.path.join(root, name)))
        if (today - filedate).days > 90:
            print name
            old_dirs.append(name)

问题是这会打印所有文件夹，但它也会打印文件夹的子文件夹，这是我不需要的。如何更改代码以便只打印文件夹？

Answer 1

打印目录后就中断:

for root, dirs, files in os.walk(path):
    for name in dirs:
        filedate = date.fromtimestamp(os.path.getmtime(os.path.join(root, name)))
        if (today - filedate).days > 90:
            print name
            old_dirs.append(name)
    break

或者考虑使用os.listdir()，它不会递归到子目录(但您必须检查结果中是否有非目录)。