我想计算所有可能组合中所有坐标 (x1, y1) 和 (x2, y2) 的斜率，而不重复。有什么办法可以自动完成吗？
#parameters
x1 = 10.18182
x2 = 13.14286
y1= (0.30097,0.31036,0.3911,0.34255,0.198374,0.398574,0.377364,0.2428,0.319312,0.13338,0.228027,0.242637,0.326533)
y2= (0.536551,0.450893,0.299292,0.286737,0.438004,0.272566,0.42541,0.430583,0.282882,0.285569,0.286261,0.439658)
#Slope
m0=(y2[0]-y1[0])/(x2-x1)
m1=(y2[1]-y1[0])/(x2-x1)
m2=(y2[2]-y1[0])/(x2-x1)
...
mn=(y2[11]-y1[12])/(x2-x1)
谢谢!
最佳答案
一行代码:m_list = [(y2_val-y1_val)/(x2-x1) for y1_val in y1 for y2_val in y2]
x1 = 10.18182
x2 = 13.14286
y1 = (0.30097,0.31036,0.3911,0.34255,0.198374,0.398574,0.377364,0.2428,0.319312,0.13338,0.228027,0.242637,0.326533)
y2 = (0.536551,0.450893,0.299292,0.286737,0.438004,0.272566,0.42541,0.430583,0.282882,0.285569,0.286261,0.439658)
m_list = [(y2_val-y1_val)/(x2-x1) for y1_val in y1 for y2_val in y2]
print m_list
关于python - 在Python中计算多个斜率，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/49247407/