python - 我不确定如何让我的字典打印我想要的信息。 Python 3.1

Question

请温柔点，我对编程很陌生，并且只拥有一本给我一些糟糕指导的书(《Head First 编程》)。这是我在 Python IDLE 中的代码:

scores = {}

scores[8.45] = 'Zach'
scores[9.12] = 'Juan'
scores[8.31] = 'Aaron'
scores[8.05] = 'Aideen'
scores[8.65] = 'Johnny'
scores[7.81] = 'Stacey'

for key in scores.keys():
    print(scores[key] + ' had a score of ' + scores[???])

该程序的目的是打印一个包含参赛者姓名及其相应分数的列表，但我不知道此时我做错了什么或对了:/

编辑:谢谢你们。在您的帮助下，我将代码编辑为工作顺序，如果您对此感兴趣，它是:

scores = {}

scores['Zach'] = 8.45

scores['Juan'] = 9.12

scores['Aaron'] = 8.31

scores['Aideen'] = 8.05

scores['Johnny'] = 8.65

scores['Stacey'] = 7.81

for key in scores.keys():    
    print(str(key), ' had a score of ' , scores[key])

Answer 1

您可以使用 {...}.items() 迭代器，如下所示:

for score,name in scores.items():
    print('{name} had a score of {score}'.format(**locals()))

但是，您的字典顺序错误。例如，如果扎克和胡安的分数相同，均为 9.10，该怎么办？然后，编写 scores[9.10]='Zach' Scores[9.10]='Juan' 将覆盖 Zach!键应该是名称。

你可以这样写:

scores['Zach'] = 8.45
scores['Juan'] = 8.45
...

---

郑重声明，以下是我从头开始的操作方法:

def parseScores(string):
    scores = {}
    for line in string.splitlines():
        if line.strip():
            name,score = line.strip().split()
            scores[name] = float(score)
    return scores

data = """
    Zach 8.45
    Juan 9.12
    Aaron 2.2
    Aideen 2.2
    Johnny 2.2
    Stacey 7.81
"""

scores = parseScores(data)
for name,score in scores.items():
    print('{name} had a score of {score}'.format(**locals()))