Python检测字符串中的两个相同的东西

Question

while testcount < 100:  
   num1=randint(0,10)
   num2=randint(0,10)
   num3=randint(0,10)
   num4=randint(0,10)
   num5=randint(0,10)
   numo=[num1,num2,num3,num4,num5]

   if #there are two 7s# in numo:
      testcount=testcount+1
      num_of_successes=num_of_successes+1
   else:
      testcount=testcount+1

    print(num_of_successes,"out of 100 there were two 7s")

如何检测“numo”中是否有两个 7？ 即使它没有使用很多代码。

Answer 1

对于一个列表，可以使用count()函数来查询count函数传入的参数中的元素在列表中有多少。

例子-

>>> l = [1,2,3,4,5,6,4]
>>> l.count(4)
2