python - ipaddress.py 在有效的 ip 地址上出现错误

Question

我正在运行 python 2.7。我下载了原始的 ipaddress.py (https://github.com/phihag/ipaddress)。我尝试运行测试以验证每个示例的 ip 地址。但即使是有效的 IP 地址似乎也是无效的。

>>> import ipaddress
>>> ipaddress.ip_address('127.0.0.1')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "ipaddress.py", line 163, in ip_address
    ' a unicode object?' % address)
ipaddress.AddressValueError: '127.0.0.1' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?
>>> ipaddress.ip_address('192.168.0.1')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "ipaddress.py", line 163, in ip_address
    ' a unicode object?' % address)
ipaddress.AddressValueError: '192.168.0.1' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?

我错过了什么？ 谢谢

Answer 1

来自docs :

Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:

我仔细检查了一下，使用 from __future__ import unicode_literals 允许您跳过 u'make_me_unicode_string' 中的 u。

>>> from __future__ import unicode_literals
>>> ipaddress.ip_address('127.0.0.1')
IPv4Address(u'127.0.0.1')