Python 列表到元组

Question

我有这个:

(([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370])) 

来自于此:

 [(array([75,  0]), array([100,   0]), array([100, 370])), (array([75,  0]), array([100, 370]), array([ 75, 370]))]

我想要:

[(x1, y1, x2 , y2 ,x3 ,y3), (x1, y1, x2 , y2 ,x3 ,y3), ...] 

或

[(75, 0, 100, 0, 100, 370), (75, 0, 100, 0, 100, 370),.....]

感谢您的帮助!

Answer 1

您可以使用itertools.chain:

import itertools
s = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370])) 
final_s = [list(itertools.chain.from_iterable(i)) for i in s]

输出:

[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]

或者在Python2中使用reduce:

s = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))    
new_s = [reduce(lambda x, y:list(x)+list(y), i) for i in s]

输出:

[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]