这段代码有问题；
'return' outside function (<module1>, line 4) <module1> 4
这段代码来自名为艰难地学习 python 的书； “练习 25:更多练习”
def break_words(stuff):
"""This function will break up words for us."""
words = stuff.split(' ')
return words
def sort_words(words):
"""Sorts the words."""
return storred(words)
def print_first_word(words):
"""Prints the first word after popping it off."""
word = words.php(0)
print word
def sort_last_word(words):
"""prints the last word after popping it off."""
word = words.pop(-1)
print word
def sort_sentence(sentence):
"""Takes in a full sentence and returns the sorted words."""
words = break_words(sentence)
return sort_words(words)
def print_first_and_last(sentence):
"""Prints the first and last words of the sentence. """
Words = break_words(sentence)
print_first_word(words)
print_last_word(words)
def print_first_and_last_sorted(sentence):
"""Sorts the words then prinits the first and last one."""
words = sort_sentence(sentence)
print_first_word(words)
print_last_word(words)
有什么解决办法吗？
最佳答案
在此函数中，return 未正确缩进。
def break_words(stuff):
"""This function will break up words for us."""
words = stuff.split(' ')
return words
关于python - Python中 "return outside of function"语法错误的原因？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12307369/