有没有更简单高效的方法来编写这段代码?这是一个计算吸烟费用的计算器。
必须有一种方法可以跳过所有的if
和elif
标签,并使其成为一个循环并节省几分钟的代码输入,并且可能有甚至成为我错过的如何键入这样的代码的“标准”。
how_many = int(input('How many ciggaretes do you smoke each day?\n'))
per_package = int(input('How much does your package cost?\n'))
contain = int(input('How many ciggaretes does the package contain?\n'))
cost_st = per_package / contain
choice = input('Do you want to calculate the cost per "Day (D)" / "Week (W)" / "Year (Y)" / "Decade (DE)"?\n')
if choice == 'D':
cost_day = cost_st * how_many
print("It will cost", cost_day ,"kr per day.")
elif choice == 'W':
cost_week = (cost_st * how_many) * 7
print('It will cost', cost_week,'kr per week.')
elif choice == 'Y':
cost_year = (cost_st * how_many) * 365
print('It will cost' ,cost_year, 'kr per year.')
elif choice == 'DE':
cost_DE = ((cost_st * how_many) * 365) * 10
print('It will cost' ,cost_DE, 'kr per decade.')
else:
print('Something went wrong! Try again please.')
最佳答案
您可以使用字典和预定义函数:
mappings = {'D': 1, 'W': 7, 'Y': 365, 'DE': 3650}
def calculate_cigarettes(arg):
cost = cost_st * how_many * mappings[arg]
print('It will cost', cost, 'kr total.')
关于python - 如何避免冗余和冗长的 if-else-结构?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30443558/