python - 如何查看数字是否以 .0 结尾

Question

如果数字以 .0 结尾，我正在尝试运行测试

我正在运行一个程序，其中的数字相差几个数量级，所以我无法估计到一定数量的数字。使用 % 也不起作用，因为某些数字被排除在外。这个程序中的所有数字都是 float ，所以我需要一种方法来检查它是否以 .0 结尾，而不是以 .00000000000001232 或它必须完全以 .0 结尾的东西

round 函数的问题是我要处理几个数量级的数字。我需要一些东西来检查它在 . 之后是否只有一位小数。或者检查小数点是否为 0 的东西。

代码:

from myro import *
from math import *


def main():

    z = 3
    a = 2
    b = 2
    x = 3
    y = 2 #starts at y = 3

    lim = 25

    c = (a**x + b**y)**(1.0/z)

    resultnum = 0    

    while z <= lim:

        while a <= lim:

            while b <= lim:

                while x <= lim:

                    while y <= lim:

                        y = y + 1
                        c = (a**x + b**y)**(1.0/z)

                        if float(int(c) + 1) != round(c, 6):
                            pass
                        else:
                            print str(a) + "^" + str(x) + " + " + str(b) + "^" + str(y) + " = " + str(int(c)+1) + "^" + str(z)
                            resultnum = resultnum + 1
                            print c

                    y = 3
                    x = x + 1

                x = 3
                b = b + 1

            b = 3
            a = a + 1

        a = 3
        z = z + 1
        print z

    print "code cycle complete"
    print str(resultnum) + " results"


main()

Answer 1

>>> n1 = 2.0
>>> int(n1) == n1 and isinstance(n1, float)
True
>>> n1 = 2
>>> int(n1) == n1 and isinstance(n1, float)
False
>>> n1 = 2.01
>>> int(n1) == n1 and isinstance(n1, float)
False
>>> n1 = 1E1         #works for scientific notation as well
>>> int(n1) == n1 and isinstance(n1, float)
True