python - 如果字符串存在于列表中，则替换整个数据框中的字符串

Question

感谢您抽出宝贵时间访问我的帖子。我在下面有以下数据框:

df1
        col1                                    col2
    1   virginia is cold, canada is cold too    virginia is cold, canada is cold too
    2   florida, virginia, washington are good  florida, virginia, washington are good
    3   georgia, alabama, virginia are hot      virginia is cold, canada is cold too
    4   virginia, ohio, new castle are great    hawaii, nebreska is wonderful
    5   hawaii, nebreska is wonderful           virginia, ohio, new castle are great

另外，我有一个包含字符串的列表:

lst = ['virginia', 'hot', 'too']

如果它与列表中的字符串之一匹配，我想用“xxxxxx”替换整个数据框中的字符串。例如，我的数据框在替换后看起来像这样:

 df1
            col1                                    col2
        1   xxxxxx is cold, canada is cold xxxxxx   xxxxxx is cold, canada is cold xxxxxx
        2   florida, xxxxxx, washington are good    florida, xxxxxx, washington are good
        3   georgia, alabama, xxxxxx are xxxxxx     xxxxxx is cold, canada is cold xxxxxx
        4   xxxxxx, ohio, new castle are great      hawaii, nebreska is wonderful
        5   hawaii, nebreska is wonderful           xxxxxx, ohio, new castle are great

到目前为止，我已经尝试过但它不起作用:

df1 = df1.replace(lst, "xxxxxx")

Answer 1

您可以根据单词列表创建字典并使用正则表达式:

lst = ['virginia', 'hot', 'too']
df1.replace({w: "xxxxxx" for w in lst}, regex=True)