Python - 使用包含键的列表从字符串中创建字典

Question

像这样:

keys = ["Name:", "Date:", "Time:sec:", "Room"]
string = "Name:BobDate:1/3Time:sec:3:00:00RoomA1"

我怎样才能得到像这样的字典:

dict1 = {"Name" : "Bob", "Date" : "1/3", "Time:sec" : "3:00:00", "Room" : "A1"}

删除冒号是可选的。 我可以完全使用 re.split()、.join() 和 map() 从字符串中删除键，但我想要而是创建字典。

Answer 1

只是一种正则表达式方式...

dict(zip(keys, re.match('(.*)'.join(keys + [""]), string).groups()))

演示:

>>> if 1:
    import re
    keys = ["Name:", "Date:", "Time:sec:", "Room"]
    string = "Name:BobDate:1/3Time:sec:3:00:00RoomA1"
    dict(zip(keys, re.match('(.*)'.join(keys + [""]), string).groups()))

{'Name:': 'Bob', 'Date:': '1/3', 'Time:sec:': '3:00:00', 'Room': 'A1'}