python - 填充特定颜色的矩形内的水印

Question

我想在图片上加水印。但只是一个文本，而是一个填充黑色的矩形，里面有一个白色文本。

目前，我只能输入文字:

from PIL import Image
from PIL import ImageFont
from PIL import ImageDraw

img = Image.open("in.jpg")

draw = ImageDraw.Draw(img)
font = ImageFont.truetype("/usr/share/fonts/truetype/ubuntu-font-family/Ubuntu-C.ttf", 66)
#font = ImageFont.truetype("Arialbd.ttf", 66)
draw.text((width - 510, height-100),"copyright",(209,239,8), font=font)
img.save('out.jpg')

Answer 1

这将在黑色矩形背景上绘制文本:

from PIL import Image, ImageFont, ImageDraw

img = Image.open("in.jpg")
width, height = img.width, img.height

draw = ImageDraw.Draw(img)
font = ImageFont.truetype(
    "/usr/share/fonts/truetype/ubuntu-font-family/Ubuntu-C.ttf", 66)
x, y = (width - 510, height-100)
# x, y = 10, 10
text = "copyright"
w, h = font.getsize(text)
draw.rectangle((x, y, x + w, y + h), fill='black')
draw.text((x, y), text, fill=(209, 239, 8), font=font)
img.save('out.jpg')

使用 imagemagick，可以制作出更好看的水印

from PIL import Image, ImageFont, ImageDraw

font = ImageFont.truetype(
    "/usr/share/fonts/truetype/ubuntu-font-family/Ubuntu-C.ttf", 66)
text = "copyright"
size = font.getsize(text)
img = Image.new('RGBA', size=size, color=(0, 0, 0, 0))
draw = ImageDraw.Draw(img)
draw.text((0, 0), text, fill=(209, 239, 8), font=font)
img.save('label.jpg')

然后调用(如果你愿意，可以通过subprocess)

composite -dissolve 25% -gravity south label.jpg in.jpg out.jpg

或者如果你用白色背景制作标签，

composite -compose bumpmap -gravity southeast label.jpg in.jpg out.jpg

---

要从 Python 脚本中运行这些命令，您可以像这样使用 subprocess:

import subprocess
import shlex

from PIL import Image, ImageFont, ImageDraw

font = ImageFont.truetype(
    "/usr/share/fonts/truetype/ubuntu-font-family/Ubuntu-C.ttf", 66)
text = "copyright"
size = font.getsize(text)
img = Image.new('RGBA', size=size, color='white')
draw = ImageDraw.Draw(img)
draw.text((0, 0), text, fill=(209, 239, 8), font=font)
img.save('label.jpg')

cmd = 'composite -compose bumpmap -gravity southeast label.jpg in.jpg out.jpg'
proc = subprocess.Popen(shlex.split(cmd))
proc.communicate()