python - 用另一个列表的内容替换列表项

Question

类似于this question ，但我不想用一个项目替换另一个项目，而是想用列表的内容替换一个项目的任何出现。

orig = [ 'a', 'b', 'c', 'd', 'c' ]
repl = [ 'x', 'y', 'z' ]
desired = [ 'a', 'b', 'x', 'y', 'z', 'd', 'x', 'y', 'z' ]

# these are all incorrect, or fail to compile
[ repl if x == 'c' else x for x in orig ]
[ [a for a in orig] if x == 'c' else x for x in orig ]
[ (a for a in orig) if x == 'c' else x for x in orig ]
[ a for a in orig if x == 'c' else x for x in orig ]

编辑:明确表示我要替换该项目的所有 次出现，而不仅仅是第一个。 (向没有在回答中涵盖该案例的任何人道歉。)

Answer 1

>>> orig = [ 'a', 'b', 'c', 'd' ]
>>> repl = [ 'x', 'y', 'z' ]
>>> desired = list(orig)  #can skip this and just use `orig` if you don't mind modifying it (and it is a list already)
>>> desired[2:3] = repl
>>> desired
['a', 'b', 'x', 'y', 'z', 'd']

当然，如果您不知道 'c' 在索引 2 处，您可以使用 orig.index('c') 找出该信息。