python - 需要帮助思考在 Python 中以整数除法拆分列表

Question

我目前有一个数据集作为列表的列表，我想按整数除法拆分它，如果有重叠则插入新数据。例如:

编辑:数据集总是升序排列。

data = [[1.565888, 2.073744], [2.073744, 2.962492], [2.962492, 4.52838], [4.52838, 5.417127], [5.417127, 6.390517], [7.025337, 7.871763]]
fix_list(data)
#[[1.565888, 2.0], [2.0, 2.073744], [2.073744, 2.962492], [2.962492, 3.0], [3.0. 4.0], [4.0, 4.52838], [4.52838, 5.0], [5.0, 5.417127], [5.417127, 6.0], [6.0, 6.390517], [7.025337, 7.871763]]

然而，当我仔细思考如何解释每种情况时，我感到很茫然，特别是在插入 [3.0, 4.0] 时，因为这是全新的信息，在之前的列表元素中不存在。

我们将一如既往地感谢您的帮助。

Answer 1

更新

这看起来不那么干净，但现在所有整数对都被输出了，即使它们不在原始数据中。另一方面，现在它是用递归生成器实现的，我认为这有点巧妙:)

---

这可能会如您所愿。 int_split 是一个生成器，它扫描输入列表，如果对具有不同的整数值，则生成剪裁到整数边界的对。该算法单独保留 [3.0, 4.0] 之类的项目，因为它们已经在整数边界上。

import math

data = [[1.565888, 2.073744], [2.073744, 2.962492], [2.962492, 4.52838], [4.52838, 5.417127], [5.417127, 6.390517], [7.025337, 7.871763], [11.1, 12.1]]

def int_split(data): 
    last_b = data[0][1] 

    for item in data: 
        a, b = item

        # First, make sure we haven't missed anything from the last loop
        if math.floor(a) - math.ceil(last_b) > 1.0:
            for x in int_split([[last_b, a]]):
                yield x

        # Did we cross an integer boundary, i.e. 
        # Is ceil(b) - floor(a) > 1.0? 
        if math.ceil(b) - math.floor(a) > 1.0: 
            # Yes, so split, making sure to include all integers between a and b

            # Find any integers in the range (and convert to floats)
            ints = [float(x) for x in range(int(math.ceil(a)), int(b))]
            for c in ints: 
                # output those values
                yield [a, c]
                a = c
            else:
                yield [a, math.floor(b)]
                yield [math.floor(b), b]
        else:
            yield item 

        # remember where we are
        last_b = b

这个输出:

[[1.565888, 2.0], [2.0, 2.073744], [2.073744, 2.962492], [2.962492, 3.0], 
 [3.0, 4.0], [4.0, 4.52838], [4.52838, 5.0], [5.0, 5.417127], [5.417127, 6.0], 
 [6.0, 6.390517], [7.025337, 7.871763], [7.871763, 8.0], [8.0, 9.0], 
 [9.0, 10.0], [10.0, 11.0], [11.0, 11.1], [11.1, 12.0], [12.0, 12.1]]