很奇怪，我有一个带有 Charfield 的模型，它有一些可能的值
class Entry(models.Model):
title = models.CharField(
max_length=100,
blank=True,
null=True,
help_text="We will refer to your entry by this title.")
production_type = models.CharField(
blank=False,
null=True,
max_length=32,
default=None,
choices= (('Agency', 'Agency'),('Brand', 'Brand'),))
当我渲染一个简单的 ModelForm 时
class EntryForm(forms.ModelForm):
class Meta:
model = Entry
fields = [
'title', 'production_type'
]
def __init__(self, request, *args, **kwargs):
self.helper = FormHelper()
self.helper.layout = Layout(
'title',
'production_type'
)
它为选择了正确状态的 production_type 字段呈现下拉列表。如果我如下添加 InlineRadios 小部件，则单选按钮在呈现时不会选择模型状态。我总是得到第一选择。表单提交正常。
class EntryForm(forms.ModelForm):
class Meta:
model = Entry
fields = [
'title', 'production_type'
]
def __init__(self, request, *args, **kwargs):
self.helper = FormHelper()
self.helper.layout = Layout(
'title',
InlineRadios('production_type', css_class='production_type_holder')
)
有什么方法可以内联单选按钮行为并跟踪我的模型状态？
最佳答案
可能有一些错误:
EntryForm有model = Entry行，而必须是model = Payment，如您描述的模型Payment- 在
EntryForm.__init__中缺少行super(EntryForm, self).__init__(*args, **kwargs) 你的
__init__声明包含冗余(？)参数request所以声明必须是def __init__(self, *args, **kwargs): #without request
请尝试此更改。
您的代码(在我的版本中，如下)在单选按钮的正常行为下工作正常，它通常会创建新的付款并打印现有的。
没有变化的 models.py
表单.py
from crispy_forms.helper import FormHelper
from crispy_forms.layout import Layout, Field, Fieldset, ButtonHolder, Submit
from crispy_forms.bootstrap import InlineRadios
class EntryForm(forms.ModelForm):
class Meta:
model = Payment # !not Entry
fields = [
'title', 'production_type'
]
def __init__(self, *args, **kwargs): #!without request
super(EntryForm, self).__init__(*args, **kwargs) #this line present
self.helper = FormHelper()
self.helper.layout = Layout(
'title',
InlineRadios('production_type'),
Submit('submit', 'Submit'), # i miss your submit button, so adding here
)
View .py
from django.views.generic.edit import CreateView
# it creates new payment
class PaymentCreate(CreateView):
model = Payment
form_class= EntryForm
template_name='payment_form.html'
success_url = '/payment/'
# this usual view just print form with already created instance
def PaymentView (request):
form = EntryForm(instance = Payment.objects.get(id=4))
c = {'form': form}
return render(request,'payment_form.html', c)
payment_form.html
{% load crispy_forms_tags %}
<html>
<head>
</head>
<body>
{% csrf_token %}
{% crispy form %}
</body>
</html>
urls.py:
...
#i made 2 views, one for 'usual' view, one for generic view
url(r'payment_view/', PaymentView),
url(r'payment/', PaymentCreate.as_view()),
...
关于python - Crispy-forms InlineRadios 不显示我的模型状态，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33882411/