python - 如何连接两个单独的字符串

Question

我需要连接两个字符串。

第一个字符串 = 日期:

(MegaMillions2019 = (date.strftime("%m%d%Y")))

第二个字符串=结果:

(results = '\n'.join([', '.join(parsed[i]) for i in range(len(parsed))])
(results.replace(' ','')))

这些字符串需要位于如下所示的同一行。

代码:

import requests
from bs4 import BeautifulSoup
from datetime import datetime

response = requests.get('https://www.lotterycorner.com/mi/mega-millions/2019')
soup = BeautifulSoup(response.text, 'html.parser')
date = soup.find_all("td", {"class":"win-nbr-date col-sm-3 col-xs-4"})
for date in date:
    date2 = (date.get_text())
    date = (datetime.strptime(date2, '%b %d, %Y'))
    MegaMillions2019 = (date.strftime("%m%d%Y"))
    print(MegaMillions2019)

data = []
for ultag in soup.find_all("ul",{"class":"nbr-grp"}):
    for litag in ultag.find_all('li'):
        results = (litag.get_text().replace(' ','').replace('MegaBall',''))
        data.append(results)

parsed = []
for i in range(int(len(data)/7)):
    j = i*7
    parsed.append(data[j:j+6])

results = '\n'.join([', '.join(parsed[i]) for i in range(len(parsed))])
print(results.replace(' ',''))

输出日期:

01222019
01182019
01152019
01112019
01082019
01042019
01012019

结果:

8,16,30,38,61,10
4,15,37,59,64,16
2,43,48,62,64,24
29,52,58,60,62,7
4,5,31,62,69,20
13,26,29,38,64,5
21,29,35,54,60,15

我希望他们像这样加入:

01222019,8,16,30,38,61,10
01182019,4,15,37,59,64,16
01152019,2,43,48,62,64,24
01112019,29,52,58,60,62,7
01082019,4,5,31,62,69,20
01042019,13,26,29,38,64,5
01012019,21,29,35,54,60,15

Answer 1

dates = []
for date in date:
    ...
    dates.append(str(MegaMillions2019))

...

parsed = []
joined = []
for i in range(int(len(data)/7)):
    j = i*7
    parsed.append(data[j:j+6])
    parsedline = [', '.join(parsed[j]) for j in range(len(parsed))][i]
    joined.append(dates[i]+', '+ parsedline)

results = '\n'.join(joined)
print(results.replace(' ',''))

演示:https://repl.it/@glhr/55449729

输出样本:

03292019,5,14,15,62,66,3
03262019,4,14,22,43,58,9