如何以 len(...)
喜欢的方式将 __len__(...)
添加到现有对象?
用例是在第一次迭代后以不需要在迭代站点之间编写/更改代码的方式记住生成器的长度。
这是我目前所拥有的:
def generator2iterator(generator):
class Iterator(object):
def __iter__(self):
i = 0
for e in generator():
i += 1
yield e
#self.__len__ = types.MethodType(lambda self: i, self)
self.__len__ = (lambda self: i).__get__(self)
return Iterator()
def test_generator():
yield 3
iterator = generator2iterator(test_generator)
print(list(iterator))
# [3]
print(iterator.__len__())
# 1
print(len(iterator))
# TypeError: object of type 'Foo' has no len()
最佳答案
定义一个保存长度的属性并为 __len__
返回它。
def generator2iterator(generator, length=None):
class Iterator(object):
def __iter__(self):
for i, e in enumerate(generator(), 1):
self._len = i
yield e
#self.__len__ = types.MethodType(lambda self: i, self)
def __len__(self):
if not hasattr(self, '_len'):
raise TypeError("object of type 'Iterator' has no defined len() yet.")
return self._len
return Iterator()
# examples:
## define a generator with 10 elements
def g():
for i in range(10):
yield i
# pass it to the iterator
it = generator2iterator(g)
# check len
len(it)
TypeError: object of type 'Iterator' has no defined len() yet.
# run the iterator
for _ in it:
pass
# check the length
len(it)
# returns:
10
关于python - 动态添加len方法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55681135/