c# - 像 alt-tab 一样枚举窗口

Question

我正在为 Vista 创建一个 alt-tab 替代品，但我在列出所有事件程序时遇到了一些问题。

我正在使用 EnumWindows 获取 Windows 列表，但这个列表很大。当我只打开 10 个窗口时，它包含大约 400 个项目。它似乎是每个控件和许多其他东西的 hwnd。

所以我必须以某种方式过滤此列表，但我无法像 alt-tab 那样完全做到这一点。

这是我现在用来过滤列表的代码。它工作得很好，但我得到了一些不需要的窗口，比如 Visual Studio 中的分离工具窗口，我也错过了像 iTunes 和 Warcraft3 这样的窗口。

private bool ShouldWindowBeDisplayed(IntPtr window)
{
    uint windowStyles = Win32.GetWindowLong(window, GWL.GWL_STYLE);

    if (((uint)WindowStyles.WS_VISIBLE & windowStyles) != (uint)WindowStyles.WS_VISIBLE ||
        ((uint)WindowExStyles.WS_EX_APPWINDOW & windowStyles) != (uint)WindowExStyles.WS_EX_APPWINDOW)
    {
        return true;
    }
    return false;
}

Answer 1

陈百强刚才回答过这个问题
( https://devblogs.microsoft.com/oldnewthing/20071008-00/?p=24863 ):

It's actually pretty simple although hardly anything you'd be able to guess on your own. Note: The details of this algorithm are an implementation detail. It can change at any time, so don't rely on it. In fact, it already changed with Flip and Flip3D; I'm just talking about the Classic Alt+Tab window here.

For each visible window, walk up its owner chain until you find the root owner. Then walk back down the visible last active popup chain until you find a visible window. If you're back to where you're started, then put the window in the Alt+Tab list. In pseudo-code:

BOOL IsAltTabWindow(HWND hwnd)
{
 // Start at the root owner
 HWND hwndWalk = GetAncestor(hwnd, GA_ROOTOWNER);

 // See if we are the last active visible popup
 HWND hwndTry;
 while ((hwndTry = GetLastActivePopup(hwndWalk)) != hwndTry) {
  if (IsWindowVisible(hwndTry)) break;
  hwndWalk = hwndTry;
 }
 return hwndWalk == hwnd;
}

点击 Chen 博客条目的链接，了解更多详细信息和一些边角条件。