我正在使用 Newtonsoft.Json 序列化程序将 C# 类转换为 JSON。对于某些类,我不需要序列化器到单个属性的实例,而是只在对象上调用 ToString,即
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
public override string ToString() { return string.Format("{0} {1}", FirstName, LastName ); }
}
我应该怎么做才能将 Person 对象序列化为 ToString() 方法的结果?我可能有很多这样的类,所以我不想最终得到一个特定于 Person 类的序列化程序,我想要一个可以适用于任何类的序列化程序(我猜是通过属性)。
最佳答案
您可以使用自定义 JsonConverter
轻松完成此操作:
public class ToStringJsonConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return true;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
writer.WriteValue(value.ToString());
}
public override bool CanRead
{
get { return false; }
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
要使用转换器,请使用 [JsonConverter]
属性装饰任何需要序列化为字符串的类,如下所示:
[JsonConverter(typeof(ToStringJsonConverter))]
public class Person
{
...
}
这是一个展示转换器的演示:
class Program
{
static void Main(string[] args)
{
Company company = new Company
{
CompanyName = "Initrode",
Boss = new Person { FirstName = "Head", LastName = "Honcho" },
Employees = new List<Person>
{
new Person { FirstName = "Joe", LastName = "Schmoe" },
new Person { FirstName = "John", LastName = "Doe" }
}
};
string json = JsonConvert.SerializeObject(company, Formatting.Indented);
Console.WriteLine(json);
}
}
public class Company
{
public string CompanyName { get; set; }
public Person Boss { get; set; }
public List<Person> Employees { get; set; }
}
[JsonConverter(typeof(ToStringJsonConverter))]
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
public override string ToString()
{
return string.Format("{0} {1}", FirstName, LastName);
}
}
输出:
{
"CompanyName": "Initrode",
"Boss": "Head Honcho",
"Employees": [
"Joe Schmoe",
"John Doe"
]
}
如果您还需要能够从字符串转换回对象,您可以在转换器上实现 ReadJson
方法,以便它查找 public static Parse(string)
方法并调用它。注意:一定要把转换器的CanRead
方法改成返回true
(或者干脆删除CanRead
重载),否则ReadJson
永远不会被调用。
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
MethodInfo parse = objectType.GetMethod("Parse", new Type[] { typeof(string) });
if (parse != null && parse.IsStatic && parse.ReturnType == objectType)
{
return parse.Invoke(null, new object[] { (string)reader.Value });
}
throw new JsonException(string.Format(
"The {0} type does not have a public static Parse(string) method that returns a {0}.",
objectType.Name));
}
当然,要使上述方法正常工作,您还需要确保在要转换的每个类上实现合适的 Parse
方法(如果它尚不存在)。对于上面显示的示例 Person
类,该方法可能如下所示:
public static Person Parse(string s)
{
if (string.IsNullOrWhiteSpace(s))
throw new ArgumentException("s cannot be null or empty", "s");
string[] parts = s.Split(new char[] { ' ' }, 2);
Person p = new Person { FirstName = parts[0] };
if (parts.Length > 1)
p.LastName = parts[1];
return p;
}
关于c# - 序列化特定类型时如何使 JSON.Net 序列化程序调用 ToString()?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22354867/