我需要上传发送额外参数的文件。
我在 stackoverflow 中找到了以下帖子:Webapi ajax formdata upload with extra parameters
它描述了如何使用 MultipartFormDataStreamProvider 并将数据保存到文件服务器来执行此操作。我不需要将文件保存到服务器,而是保存到数据库。 我已经有使用 MultipartMemoryStreamProvider 的工作代码,但它不使用额外的参数。
你能告诉我如何在 webapi 中处理额外的参数吗?
例如,如果我添加文件并测试参数:
data.append("myParameter", "test");
这是我的 webapi,它在没有额外参数的情况下处理文件上传:
if (Request.Content.IsMimeMultipartContent())
{
var streamProvider = new MultipartMemoryStreamProvider();
var task = Request.Content.ReadAsMultipartAsync(streamProvider).ContinueWith<IEnumerable<FileModel>>(t =>
{
if (t.IsFaulted || t.IsCanceled)
{
throw new HttpResponseException(HttpStatusCode.InternalServerError);
}
_fleDataService = new FileDataBLL();
FileData fle;
var fleInfo = streamProvider.Contents.Select(i => {
fle = new FileData();
fle.FileName = i.Headers.ContentDisposition.FileName;
var contentTest = i.ReadAsByteArrayAsync();
contentTest.Wait();
if (contentTest.Result != null)
{
fle.FileContent = contentTest.Result;
}
// get extra parameters here ??????
_fleDataService.Save(fle);
return new FileModel(i.Headers.ContentDisposition.FileName, 1024); //todo
});
return fleInfo;
});
return task;
}
最佳答案
扩展 gooid 的答案,我将 FormData 提取封装到提供程序中,因为我在引用它时遇到问题。在我看来,这只是提供了更好的实现。
public class MultipartFormDataMemoryStreamProvider : MultipartMemoryStreamProvider
{
private readonly Collection<bool> _isFormData = new Collection<bool>();
private readonly NameValueCollection _formData = new NameValueCollection(StringComparer.OrdinalIgnoreCase);
private readonly Dictionary<string, Stream> _fileStreams = new Dictionary<string, Stream>();
public NameValueCollection FormData
{
get { return _formData; }
}
public Dictionary<string, Stream> FileStreams
{
get { return _fileStreams; }
}
public override Stream GetStream(HttpContent parent, HttpContentHeaders headers)
{
if (parent == null)
{
throw new ArgumentNullException("parent");
}
if (headers == null)
{
throw new ArgumentNullException("headers");
}
var contentDisposition = headers.ContentDisposition;
if (contentDisposition == null)
{
throw new InvalidOperationException("Did not find required 'Content-Disposition' header field in MIME multipart body part.");
}
_isFormData.Add(String.IsNullOrEmpty(contentDisposition.FileName));
return base.GetStream(parent, headers);
}
public override async Task ExecutePostProcessingAsync()
{
for (var index = 0; index < Contents.Count; index++)
{
HttpContent formContent = Contents[index];
if (_isFormData[index])
{
// Field
string formFieldName = UnquoteToken(formContent.Headers.ContentDisposition.Name) ?? string.Empty;
string formFieldValue = await formContent.ReadAsStringAsync();
FormData.Add(formFieldName, formFieldValue);
}
else
{
// File
string fileName = UnquoteToken(formContent.Headers.ContentDisposition.FileName);
Stream stream = await formContent.ReadAsStreamAsync();
FileStreams.Add(fileName, stream);
}
}
}
private static string UnquoteToken(string token)
{
if (string.IsNullOrWhiteSpace(token))
{
return token;
}
if (token.StartsWith("\"", StringComparison.Ordinal) && token.EndsWith("\"", StringComparison.Ordinal) && token.Length > 1)
{
return token.Substring(1, token.Length - 2);
}
return token;
}
}
下面是我的使用方法。请注意,由于我们使用的是 .NET 4.5,所以我使用了 await。
[HttpPost]
public async Task<HttpResponseMessage> Upload()
{
if (!Request.Content.IsMimeMultipartContent())
{
return Request.CreateResponse(HttpStatusCode.UnsupportedMediaType, "Unsupported media type.");
}
// Read the file and form data.
MultipartFormDataMemoryStreamProvider provider = new MultipartFormDataMemoryStreamProvider();
await Request.Content.ReadAsMultipartAsync(provider);
// Extract the fields from the form data.
string description = provider.FormData["description"];
int uploadType;
if (!Int32.TryParse(provider.FormData["uploadType"], out uploadType))
{
return Request.CreateResponse(HttpStatusCode.BadRequest, "Upload Type is invalid.");
}
// Check if files are on the request.
if (!provider.FileStreams.Any())
{
return Request.CreateResponse(HttpStatusCode.BadRequest, "No file uploaded.");
}
IList<string> uploadedFiles = new List<string>();
foreach (KeyValuePair<string, Stream> file in provider.FileStreams)
{
string fileName = file.Key;
Stream stream = file.Value;
// Do something with the uploaded file
UploadManager.Upload(stream, fileName, uploadType, description);
// Keep track of the filename for the response
uploadedFiles.Add(fileName);
}
return Request.CreateResponse(HttpStatusCode.OK, "Successfully Uploaded: " + string.Join(", ", uploadedFiles));
}
关于c# - 带有额外参数的 Webapi 表单数据上传(到 DB),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19723064/