python - 如何让剪刀石头布游戏的代码不那么冗余？

Question

我要做一个石头剪刀布游戏的项目，目前我的代码是游戏的完整代码，但我的教授不喜欢它，因为它太冗余了。有没有办法缩短它或使其更简单？

import random

while True:
bot = random.choice(["Rock", "Paper", "Scissors"]).lower()

user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: \n ").lower()
if user_choice == bot:
   print("We tied! I chose", bot," and you chose", user_choice)
elif user_choice == "rock":
   if bot == "paper":
      print("You lose! I chose", bot," and you chose", user_choice , ", Paper beats rock!")
   elif bot == "scissors":
      print("You win! I chose", bot," and you chose", user_choice , ", Rock beat scissors!")
elif user_choice == "paper":
   if bot == "rock":
      print("You win! I chose",bot," and you chose", user_choice , ", Paper beats rock!")
   elif bot == "scissors:":
      print("You lose! I chose", bot," and you chose", user_choice , ", Scissors beats paper")
elif user_choice == "scissors":
   if bot == "paper":
      print("You win! I chose", bot," and you chose",user_choice, ", Scissors beats paper")
   elif bot == "rock":
      print("You Lose! I chose", bot," and you chose", user_choice , ", Rock beats scissors")
else:
print("Invalid Entry, you typed:", user_choice, ", Please try again: ")

if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
exit()

有时当我输入 paper 作为输入时，我没有得到输出，代码只是循环回到开头，有人知道为什么会这样吗？

例子: 选择剪刀石头布或 -1 退出:

摇滚

你赢了!我选剪刀，你选石头，石头打剪刀!

选择剪刀石头布或 -1 退出:

纸

我们打成平手了!我选纸你选纸

选择剪刀石头布或 -1 退出:

纸

选择剪刀石头布或 -1 退出: ^无输出

剪刀

你输了!我选石头你选剪刀，石头打剪刀

选择剪刀石头布或 -1 退出:

纸

选择剪刀石头布或 -1 退出:

^ 没有输出

Answer 1

我建议使用取模运算符并枚举您的选择。 (石头(0)=> 布(1)=> 剪刀(2))

获胜条件是 user_choice - bot 选择 %3 == 1。