我正在尝试通过 apache 和 mod_wsgi 托管我的 python 3.4 flask 应用程序。通过 flask 自己的服务器运行应用程序工作正常。该应用程序是在虚拟环境 pyvenv-3.4 中制作的。
但是,当尝试在浏览器中连接到 apache 服务器时,它会抛出 500 http 错误。附上配置和日志。我认为这与使用 pyvenv 而不是 virtualenv(来自 pip)有关。 Flask 文档告诉我使用这一行激活虚拟环境
activate_this = '/path/to/env/bin/activate_this.py'
但是,由于文件不存在,这会产生 IOError。我试着将它指向“激活”文件,然后是 activate.csh、activate.fish,但没有成功。所有文件都会在停用行上产生 SyntaxError。
如何使用我的 virtualenv 通过 Apache 运行这个应用程序?
flaskapp.wsgi
#!/usr/bin/python
activate_this = '/var/www/FlaskApp/FlaskApp/bin/activate'
execfile(activate_this, dict(__file__=activate_this))
import sys
import logging
logging.basicConfig(stream=sys.stderr)
sys.path.insert(0,"/var/www/FlaskApp/")
from FlaskApp import app as application
application.secret_key = 'some secret key'
Apache 虚拟主机
<VirtualHost *:80>
ServerName example.org # my server name
ServerAlias gallifrey 192.168.0.84
ServerAdmin admin@example.org # my admin
WSGIScriptAlias /flask /var/www/FlaskApp/flaskapp.wsgi
<Directory /var/www/FlaskApp/FlaskApp/>
Order allow,deny
Allow from all
</Directory>
Alias /static /var/www/FlaskApp/FlaskApp/static
<Directory /var/www/FlaskApp/FlaskApp/static/>
Order allow,deny
Allow from all
</Directory>
ErrorLog ${APACHE_LOG_DIR}/error.log
LogLevel warn
CustomLog ${APACHE_LOG_DIR}/access.log combined
</VirtualHost>
层次结构
/var/www/FlaskApp
flaskapp.wsgi
FlaskApp/
bin/
activate
activate.csh
activate.fish
easy_install, easy_install-3.4
pip, pip3, pip3.4
python, python3, python3.4
include/
lib/
scripts/
static/
templates/
app.py
__init__.py
尝试打开网页时出现 http 500 错误:
Apache error.log
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] mod_wsgi (pid=31629): Target WSGI script '/var/www/FlaskApp/flaskapp.wsgi' cannot be loaded as Python module.
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] mod_wsgi (pid=31629): Exception occurred processing WSGI script '/var/www/FlaskApp/flaskapp.wsgi'.
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] Traceback (most recent call last):
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] File "/var/www/FlaskApp/flaskapp.wsgi", line 3, in <module>
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] execfile(activate_this, dict(__file__=activate_this))
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] File "/var/www/FlaskApp/FlaskApp/bin/activate", line 4
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] deactivate () {
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] ^
[Fri May 02 10:22:58 2014] [error] [client 192.168.0.81] SyntaxError: invalid syntax
最佳答案
您可以关注 VirtualEnvironments instructions ,或者您可以复制 virtualenv
的 activate_this.py
脚本的作用:
import sys
import os
old_os_path = os.environ['PATH']
os.environ['PATH'] = os.path.dirname(os.path.abspath(__file__)) + os.pathsep + old_os_path
base = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
if sys.platform == 'win32':
site_packages = os.path.join(base, 'Lib', 'site-packages')
else:
site_packages = os.path.join(base, 'lib', 'python%s' % sys.version[:3], 'site-packages')
prev_sys_path = list(sys.path)
import site
site.addsitedir(site_packages)
sys.real_prefix = sys.prefix
sys.prefix = base
# Move the added items to the front of the path:
new_sys_path = []
for item in list(sys.path):
if item not in prev_sys_path:
new_sys_path.append(item)
sys.path.remove(item)
sys.path[:0] = new_sys_path
你可以把它变成一个更通用的函数:
import sys
import os
def activate_venv(path):
if sys.platform == 'win32':
bin_dir = os.path.join(path, 'Scripts')
site_packages = os.path.join(base, 'Lib', 'site-packages')
else:
bin_dir = os.path.join(path, 'bin')
site_packages = os.path.join(BASE, 'lib', 'python%s' % sys.version[:3], 'site-packages')
os.environ['PATH'] = bin_dir + os.pathsep + os.environ['PATH']
prev_sys_path = list(sys.path)
import site
site.addsitedir(site_packages)
sys.prefix, sys.real_prefix = path, sys.prefix
# Move the added items to the front of the path:
new_sys_path = []
for item in list(sys.path):
if item not in prev_sys_path:
new_sys_path.append(item)
sys.path.remove(item)
sys.path[:0] = new_sys_path
将其放入默认 Python 模块搜索路径的模块中,导入 activate_venv
并传入 os.path.dirname(os.path.abspath(__file__))
:
from somemodule import activate_venv
import os.path
activate_venv(os.path.dirname(os.path.abspath(__file__)))
关于python - FlaskApp 使用 mod_wsgi 在 apache 中返回 http 500,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23424325/