ios - 根据键值之一删除 CNContact 数组

Question

我是一个敏捷的新手，正在尝试使用 Contacts 框架，但遇到了一个问题:-

我有一个名为 contacts 的 CNContact 数组，键为 givenName、familyName 和 phoneNumbers 。 我想从 contacts

数组中过滤掉定义为 String 类型的某些 names

我试过:

for name in namesToRemove { // 'name' is always in fullname format
    contacts = contacts.filter () { $0.givenName + " " + $0.familyName != name }
}

但仅当同时指定了 givenName 和 familyName 时，删除才有效。

另外，请记住，在 iPhone 设备上，某些联系人的全名仅在其“名字”或“姓氏”列中指定。

我该怎么做？非常感谢!

Answer 1

您可以将 contains 用于 namesToRemove 数组，作为对 contacts 进行 filter 操作的条件:

let filteredContacts = contacts.filter { !namesToRemove.contains($0.givenName) }

我们首先设置一个CNContact 示例结构(因为您没有向我们提供最小的工作示例...)

/* example setup */
struct CNContact {
    let givenName: String
    let familyName: String
    let phoneNumbers: [String]
    init(_ givenName: String, _ familyName: String, 
         _ phoneNumbers: [String]) { 
        self.givenName = givenName
        self.familyName = familyName
        self.phoneNumbers = phoneNumbers
    }
} 

let contacts = [CNContact("David", "Scott",   ["123-567", "010-111"]),
                CNContact("Lisa",  "Rowling", ["134-521", "121-731"]),
                CNContact("Brad",  "Knight",  ["621-141", "551-723"]),
                CNContact("David", "Phelps",  ["652-723", "718-888"]),
                CNContact("Sarah", "Bright",  ["166-720", "378-743"])]

示例用法:

/* example #1: 
   filter by removing any contacts that whose 'givenName' property
   are contained in a list of given surnames to remove 'namesToRemove' */
let namesToRemove1 = ["David", "Sarah"]
let filteredContacts1 = contacts.filter { !namesToRemove1.contains($0.givenName) }

filteredContacts1.forEach { 
    print($0.givenName, $0.familyName, $0.phoneNumbers.first ?? "none") 
} /* Lisa Rowling 134-521
     Brad Knight 621-141 */

/* example #2: 
   filter by removing any contacts that whose 'givenName' and 'familyName'
   properties are contained in a list of given full names to remove ('namesToRemove'), 
   where we know these full names are separated by exactly a single whitespace */
let namesToRemove2 = ["David Phelps", "Sarah Bright"]
let filteredContacts2 = contacts.filter { 
    !namesToRemove2.contains($0.givenName + " " + $0.familyName) }

filteredContacts2.forEach { 
    print($0.givenName, $0.familyName, $0.phoneNumbers.first ?? "none") 
} /* David Scott 123-567
     Lisa Rowling 134-521
     Brad Knight 621-141  */

最后，基于您问题的后续更新的附加示例:

/* example #3: 
   filter by removing any contacts where at least one of the following
   holds: 
   1. 'givenName' + " " + 'familyName' equals a name in 'namesToRemove',
   2. 'givenName' by itself equals a name in 'namesToRemove',
   3. 'familyName' by itself equals a name in 'namesToRemove', */

let contacts2 = [CNContact("David", "Scott",   ["123-567", "010-111"]),
                CNContact("Lisa",  "Rowling", ["134-521", "121-731"]),
                CNContact("",  "Brad Knight",  ["621-141", "551-723"]),
                CNContact("David Phelps", "",  ["652-723", "718-888"]),
                CNContact("Sarah", "Bright",  ["166-720", "378-743"])]
   print(" ")
let namesToRemove3 = ["David Phelps", "Sarah Bright", "Brad Knight"]
let filteredContacts3 = contacts2.filter { 
    !(namesToRemove3.contains($0.givenName + " " + $0.familyName) ||
      namesToRemove3.contains($0.givenName) ||
      namesToRemove3.contains($0.familyName)) }

filteredContacts3.forEach { 
    print($0.givenName, $0.familyName, $0.phoneNumbers.first ?? "none") 
} /* David Scott 123-567
     Lisa Rowling 134-521 */