我正在尝试实现一个搜索栏,以便根据搜索查询填充表格 View 。我只是在这里寻找用户名。
数据结构:
"Users"
-"UID"
-"Username"
我有一个查询运行在搜索栏中输入的文本。我可以很好地打印搜索结果,所以我知道他们会回来。但是,我无法从查询闭包中拆分数据,也不知道该怎么做
我尝试构建一个内部数组,然后将外部数组设置为它,但它始终包含零值。我知道我的 for 循环正在运行并且我知道正在返回值。他们只是没有被保存。
self.filteredNameList = []
let searchText = searchText.lowercased()
let userQuery = ref.queryOrdered(byChild: "username").queryStarting(atValue: searchText)
userQuery.observeSingleEvent(of: .value, with: { (snapshot) in
for snap in snapshot.children {
let userSnap = snap as! FIRDataSnapshot
let userDict = userSnap.value as! [String: AnyObject]
let name = userDict["username"] as! String
self.filteredNameList.append(name)
}
self.tableView.reloadData()
print("Inside closure: \(self.filteredNameList)")
})
print("Outside closure: \(self.filteredNameList)")
}
我该怎么办?谢谢 - 基南
最佳答案
这是一个经过测试的例子
给定一个 Firebase 结构
users
uid_0
name: "bill"
uid_1
name: "leroy"
uid_2
name: "frank"
uid_3
name: "leon"
我们想返回所有以'le'开头的节点并将它们存储在一个数组中
var namesArray = [String]() //note this is stored outside the function so other
//functions can access it.
func getSomeLe() {
self.namesArray = [] //init it any time this func is called.
let usersRef = ref.child("users")
let queryRef = usersRef.queryOrdered(byChild: "name").queryStarting(atValue: "le")
queryRef.observeSingleEvent(of: .value, with: { (snapshot) in
for snap in snapshot.children {
let userSnap = snap as! FIRDataSnapshot
let uid = userSnap.key
let userDict = userSnap.value as! [String:AnyObject]
let name = userDict["name"] as! String
self.namesArray.append(name)
}
print(self.namesArray)
})
}
将数据存入数组并打印
["乐华","莱昂"]
关于ios - 从 Firebase 查询创建 TableView (iOS、Swift),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41642690/