ios - 如何将 xml 字符串分成元组？

Question

我想将 XML 字符串转换为元组。

var responseXml =
"""
<?xml version="1.0"?>
<tmweb>
<booking type='come' time='71102' persnr='9999' name='Test' firstname='Max' title='Mr.'/>
</tmweb>
"""

responseXml.removeFirst(39)                                          // Remove the beginning of the XML
responseXml.removeLast(11)                                           // Remove the end of the XML
responseXml = responseXml.replacingOccurrences(of:" ", with: ";")   // Replace empty place with ;
responseXml = responseXml.replacingOccurrences(of: "'", with: "\"")    // Replace ' to "
responseXml = responseXml.replacingOccurrences(of: "=", with: ": ")    // Replace = to :(space)

临时输出:

"type: "come";time: "71102";persnr: "9999";name: "Test";firstname: "Max";title: "Mr."\n"

目前我只有整个字符串作为 UIAlert 的替换

我的下一步:

我想将秒 (71102) 转换为可读的时间格式，例如 19:45:22

func secs2time (_ seconds : Int) -> (Int,Int,Int) {
    return (seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)
}

目前很难找到好的解决方案。

有什么建议吗？

Answer 1

要处理xml，您需要使用NSXMLParser。这里有两个网站可以为您提供帮助。

http://leaks.wanari.com/2016/08/24/xml-parsing-swift/ https://medium.com/@lucascerro/understanding-nsxmlparser-in-swift-xcode-6-3-1-7c96ff6c65bc

这是一个小例子:

var url = NSURL(string: "http://example.com/website-with-xml")
var xmlParser = NSXMLParser(contentsOfURL: url)
xmlParser.delegate = self
xmlParser.parse()

func parser(parser: NSXMLParser!, didStartElement elementName: String!, namespaceURI: String!, qualifiedName qName: String!, attributes attributeDict: NSDictionary!) {
   println("Element's name is \(elementName)")
   println("Element's attributes are \(attributeDict)")
}

时间转换可以在其他问题here中找到在计算器中:

Define

func secondsToHoursMinutesSeconds (seconds : Int) -> (Int, Int, Int) {
  return (seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)
}

Use

secondsToHoursMinutesSeconds(27005) (7,30,5)

or

let (h,m,s) = secondsToHoursMinutesSeconds(27005)

The above function makes use of Swift tuples to return three values at once. You destructure the tuple using the let (var, ...) syntax or can access individual tuple members, if need be.

If you actually need to print it out with the words Hours etc then use something like this:

func printSecondsToHoursMinutesSeconds (seconds:Int) -> () {
  let (h, m, s) = secondsToHoursMinutesSeconds (seconds)
  print ("\(h) Hours, \(m) Minutes, \(s) Seconds")
}

Note that the above implementation of secondsToHoursMinutesSeconds() works for Int arguments. If you want a Double version you'll need to decide what the return values are - could be (Int, Int, Double) or could be (Double, Double, Double). You could try something like:

func secondsToHoursMinutesSeconds (seconds : Double) -> (Double, Double, Double) {
  let (hr,  minf) = modf (seconds / 3600)
  let (min, secf) = modf (60 * minf)
  return (hr, min, 60 * secf)
}