iOS( swift ): Location of touch event in UIButton programatically

Question

我有一个 UIButton 实例，我想获取触摸的确切位置，即使触发附加到它的选择器也是如此。

按钮配置如下:

private var button: UIButton!

private func setupButton() {
    button = UIButton(frame: frame)
    button.addTarget(self, action: #selector(buttonPressed), for: .touchUpInside)
}

@objc private func buttonPressed(_ button: BounceButton) {
    // I need the location of the touch event that triggered this method.
}

请问触发buttonPressed方法的触摸事件定位的实现方法是什么？我对使用 UIGestureRecognizer 实例犹豫不决，因为我实际上有多个具有不同 tag 值的按钮，我用它们在 buttonPressed 中执行不同的操作方法。

感谢您的任何建议。

Answer 1

选项 1

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
  if let touch = touches.first {
     let position = touch.location(in: view)
      if button.frame.contains(position) {

      }
  }
}

选项2

添加手势和访问按钮使用

@objc func tapped(_ gesture:UITapGestureRecognizer)
{
    print(gesture.view?.tag)
    print(gesture.location(in: gesture.view))
}

手势. View