我在同一屏幕上处理 2 个表时遇到问题。每次他总是崩溃。有人可以帮助我吗?
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
var cell: TableViewCellComunicazioni?
if tableView == self.tableViewNotifica {
cell = tableView.dequeueReusableCell(withIdentifier: "cellNotifica", for: indexPath) as? TableViewCellComunicazioni
let dataNotifica = structNotifica[indexPath.row].dateNotifica
let testoNotifica = structNotifica[indexPath.row].textNotifica
cell?.dateNotification.text = "\(date!)"
cell?.textNotification.text = "\(text!)"
return cell!
}
if tableView == self.tableViewInbox {
cell = tableView.dequeueReusableCell(withIdentifier: "cellInbox", for: indexPath) as? TableViewCellComunicazioni
let email = structInbox[indexPath.row].email
let messaggio = structInbox[indexPath.row].messaggio
let data = structInbox[indexPath.row].data
cell?.emailInbox.text = "\(email!)"
cell?.messaggioInbox.text = "\(message!)"
cell?.dataInbox.text = "\(date!)"
return cell!
}
return UITableViewCell()
}
最佳答案
这可能是解决您的问题的方法:
代码示例:
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if tableView == self.tableViewNotifica {
let cell = tableView.dequeueReusableCell(withIdentifier: "cellNotifica", for: indexPath) as? TableViewCellComunicazioni
let dataNotifica = structNotifica[indexPath.row].dateNotifica
let testoNotifica = structNotifica[indexPath.row].textNotifica
cell?.dateNotification.text = "\(date!)"
cell?.textNotification.text = "\(text!)"
return cell!
}
if tableView == self.tableViewInbox {
let cell = tableView.dequeueReusableCell(withIdentifier: "cellInbox", for: indexPath) as? TableViewCellComunicazioni
let email = structInbox[indexPath.row].email
let messaggio = structInbox[indexPath.row].messaggio
let data = structInbox[indexPath.row].data
cell?.emailInbox.text = "\(email!)"
cell?.messaggioInbox.text = "\(message!)"
cell?.dataInbox.text = "\(date!)"
return cell!
}
return UITableViewCell()
}
并确保您具有正确的出列单元格标识符。
extension ViewController : UITableViewDelegate,UITableViewDataSource {
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return listmoviesArray.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if tableView == moviesTableView {
let cell = tableView.dequeueReusableCell(withIdentifier: "MovieTableViewCell", for: indexPath) as! MovieTableViewCell
cell.delegate = self
cell.setupCell(listmoviesArray[indexPath.row],indexPath: indexPath)
return cell
} else {
let cell = tableView.dequeueReusableCell(withIdentifier: "MovieTableViewCell2", for: indexPath) as! MovieTableViewCell
cell.delegate = self
cell.setupCell(listmoviesArray[indexPath.row],indexPath: indexPath)
return cell
}
}
func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
if tableView == moviesTableView {
// Handle your selection for row.
} else {
//Handle your selection for row.
}
}
}
以上代码使用 2 个 Tableview 产生以下输出。
关于swift - 在同一个 View Controller 中使用 2 个 TableView (Swift 4),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54251473/