arrays - 从 "cards"集合数组快速发牌给玩家

Question

我有一个名为 shuffledDeck 的数组，其中包含 52 个已洗牌的 Int 数字我想分别处理给每个玩家

func dealCards1(){
    for i in 0...25{
        comp1PlayDeck += shuffledDeck[i]
    }
} 

不太确定我应该返回什么我这样做是为了学习而不是为了任何重要的事情 只是想知道我应该为 exmp 的函数声明做些什么

func dealCards1(Int: Array) -> Int: Array{}

我不确定如何返回数组任何帮助将不胜感激谢谢! :D 这是到目前为止的完整代码

import Foundation

let comp1 = 1
let comp2 = 2

var dealDeck =     [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52]
var shuffledDeck: [Int]

var comp1PlayDeck = [Int]()
var comp2PlayDeck: [Int]

var comp1WinDeck: [Int]
var comp2WinDeck: [Int]

var comp1CurrCard: Int
var comp2CurrCard: Int



//functions
    //shuffles cards from dealDeck returns to shuffledDeck
func shuffle<T>(var list: Array<T>) -> Array<T> {
    for i in 0..<list.count {
        let j = Int(arc4random_uniform(UInt32(list.count - i))) + i
        list.insert(list.removeAtIndex(j), atIndex: i)
    }
    return list
}
//shuffle deck
 shuffledDeck = shuffle(dealDeck)

for num in shuffledDeck {
    println(num)
}
//deals to player one
func dealCards1() -> [Int] {
    for i in 0...25{
        comp1PlayDeck += shuffledDeck[i]
    }
    return comp1PlayDeck
}
//deals to player two
func dealCards2(){

}
comp1PlayDeck = dealCards1()

Answer 1

您是在问如何从函数中返回处理过的 comp1PlayDeck？如果是这样，只需让函数返回一个 Int 数组并在函数末尾返回 comp1PlayDeck。

var comp1PlayDeck = [Int]()
func dealCards1() -> [Int] { 
    for i in 0...25{            
        comp1PlayDeck += shuffledDeck[i]
    }
    return comp1PlayDeck
}