我正在尝试循环一个具有特定计数次数的计时器... 例如... 1, 2, 3, 4, 5
然后再循环,同样计数,10次,然后停止。
我可以进行计数,但无法进行循环计数。
我做错了什么?
var times = 0
var stopCounting = 10
@IBAction func buttonPressed(sender: UIButton) {
self.startTimer()
}
func startTimer(){
self.timer = NSTimer.scheduledTimerWithTimeInterval(1.0, target: self, selector: Selector("startCounting"), userInfo: nil, repeats: true)
}
func startCounting (){
times += 1
if times < stopCounting + 1{
if counter > -1 && counter < 6 {
counting.text = String(counter++)
} else if counter == Int(counting.text) {
counting.text = "0"
}
}
最佳答案
import UIKit
class ViewController: UIViewController {
@IBOutlet weak var strTime: UILabel!
var timer = NSTimer()
var endTime: NSTimeInterval = 0
var now: NSTimeInterval { return NSDate().timeIntervalSinceReferenceDate }
var times = 0
override func viewDidLoad() {
super.viewDidLoad()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
func updateText(){
let time = Int(ceil(endTime - now))
if time == 0 {
times++
if times == 10 {
strTime.text = "end"
timer.invalidate()
}
endTime = NSDate().timeIntervalSinceReferenceDate + 5
} else {
strTime.text = time.description
}
}
@IBAction func buttonPressed(sender: UIButton) {
timer = NSTimer.scheduledTimerWithTimeInterval(0.1, target: self, selector: "updateText", userInfo: nil, repeats: true)
endTime = NSDate().timeIntervalSinceReferenceDate + 5
sender.hidden = true
}
}
要使其从 1 计数到 5,您需要将 ceil 更改为 floor,abs() 并添加 +1
func updateText(){
let time = Int(floor(abs(endTime - now - 5)))
if time == 5 {
times++
if times == 10 {
strTime.text = "10" + " " + "0"
timer.invalidate()
}
endTime = NSDate().timeIntervalSinceReferenceDate + 5
} else {
strTime.text = times.description + " " + (time+1).description
}
}
关于swift - 如何使用特定数量的计数在 SWIFT 中循环 NSTimer,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29873055/