ios - 如何在按钮触及内部时从 Superview 中删除以编程方式创建的 subview ?

标签 ios swift uiview subview

enter image description here

我有一个系统,当用户点击另一个按钮(名为 Button)时,它会生成新 View (在图片上标有蓝色矩形)和按钮(标有绿色圆圈)作为 Superview 的 subview (标有红色矩形) .他们都是以编程方式创建的。我可以根据它的带有操作消息的 button.tag 删除“减号按钮”。问题是如何删除减号按钮旁边的 subview ?它也有与减号按钮相同的标签。

下面是我的 mainButton IBAction ;

 @IBAction func mainButton(sender: UIButton) {
        drawThem()


        minusButtonY = counter == 0 ? (minusButtonY + 101) :(minusButtonY + 68)
        borderY = counter == 0 ? (borderY + 86) : (borderY + 68)
        counter++
        drawFooter()
        completePaymentView.contentSize = counter > 7 ? (CGSizeMake(500.0, ( borderY ))) : (CGSizeMake(500.0, ( 490.0 )))

    }        

以及生成新 View 和按钮的方法;

func drawThem() {
      //creating minus button
            let image = UIImage(named: "minus.png") as UIImage?
            let button   = UIButton.buttonWithType(UIButtonType.Custom) as! UIButton
            var mX : CGFloat = 2.0
            var mY : CGFloat = minusButtonY >= 36.0 ? minusButtonY : 36.0

            button.frame = CGRectMake(mX, mY, 22, 22)
            button.setImage(image, forState: .Normal)
            button.tag = Int(counter)
            button.addTarget(self, action:"btnTouched:", forControlEvents:.TouchUpInside)
            completePaymentView.addSubview(button)

            //drawing payment section border
            var x : CGFloat = 43.0
            var y : CGFloat = borderY >= 20.0 ? borderY : 20.0

            let size = CGSize(width: 485 , height: 55)

            let borderView = UIView(frame: CGRect(origin: CGPoint(x: x , y: y), size: size))
            borderView.layer.borderColor = UIColor(red: 0.83, green: 0.85, blue: 0.88, alpha: 1.0).CGColor
            borderView.layer.borderWidth = 2.0
            borderView.layer.cornerRadius = 5.0
            borderView.tag = counter
            completePaymentView.addSubview(borderView)

            //drawing UIImage and Labels into border
            let imageName = "circle.png"
            let thumb = UIImage(named: imageName)
            let imageView = UIImageView(image: thumb!)
            imageView.frame = CGRect(x: 14, y: 8, width: 55, height: 35)
            borderView.addSubview(imageView)


            let label1 = UILabel(frame: CGRect(x: 85, y: 20, width: 100, height: 18)) as UILabel
           label1.text = "Some Text"
           label1.textColor = UIColor(red: 0.49, green: 0.54, blue: 0.6, alpha: 1.0)
           label1.font = label1.font.fontWithSize(14.0)
           label1.textAlignment = .Left
            borderView .addSubview(label1)

            let label2 = UILabel(frame: CGRect(x: 370, y: 20, width: 100, height: 18)) as UILabel
            label2.text = "Some Text"
            label2.textColor = UIColor(red: 0.49, green: 0.54, blue: 0.6, alpha: 1.0)
            label2.font = label2.font.fontWithSize(14.0)
            label2.textAlignment = .Right
            borderView .addSubview(label2)


        }

和下面的目标操作;

func btnTouched(button : UIButton){

    button.removeFromSuperview()


}

最佳答案

在 btnTouched 方法中添加以下内容。实际上,我正在搜索所有 subview 以查找标签。

for view in self.view.subviews as! [UIView] {
    if view.tag == button.tag {
    view.removeFromSuperview()

  }
}

关于ios - 如何在按钮触及内部时从 Superview 中删除以编程方式创建的 subview ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32400659/

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