在 swift 2 中,当我与网络服务通信时,当我在按钮操作中编写这些代码时,它工作正常。
let alert = UIAlertController(title: "Alert", message: "Message", preferredStyle: .Alert)
let ok = UIAlertAction(title: "OK", style: .Default, handler: { (action) -> Void in })
alert.addAction(ok);
let request = NSMutableURLRequest(URL: NSURL(string: "http://www.myaddress.com/web-service/iostest.aspx")!)
request.HTTPMethod = "POST"
var postString = String();
postString = "uid=1";
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
guard error == nil && data != nil else {
alert.title="Error"
alert.message = "Connection error"
dispatch_async(dispatch_get_main_queue()){
self.presentViewController(alert, animated: true, completion: nil)
}
return
}
if let httpStatus = response as? NSHTTPURLResponse where httpStatus.statusCode != 200 {
alert.title="Error"
alert.message = "Server error"
dispatch_async(dispatch_get_main_queue()){
self.presentViewController(alert, animated: true, completion: nil)
}
}
let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
alert.title="Info"
alert.message = responseString as? String
dispatch_async(dispatch_get_main_queue()){
self.presentViewController(alert, animated: true, completion: nil)
}
}
task.resume()
正如我所说,这工作正常,但因为我也想从不同的 ViewControls 执行此操作,所以我创建了一个 swift 文件,其中包含一个结构和该结构中的一个静态函数,该函数返回“responseString”,因此我可以提醒它在 View 控件中。像这样:
struct globalClass {
static func sendInfo(url: String, data: String) -> (answer: String, errorCode: Int32) {
var res = String();
var err = Int32();
err = 0;
let request = NSMutableURLRequest(URL: NSURL(string: url)!);
request.HTTPMethod = "POST";
let postString: String = data;
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding);
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
guard error == nil && data != nil else {
err = 1;
return;
}
if let httpStatus = response as? NSHTTPURLResponse where httpStatus.statusCode != 200 {
err = 2;
return;
}
let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding);
res = (responseString as? String)!;
}
task.resume();
return (res, err);
}
但是现在当我从我的按钮调用这个函数时,它很快向我显示一个空警报,它似乎没有从网络服务中获得任何东西,甚至没有尝试过。
我将这些放在按钮操作中:
@IBAction func btnData(sender: AnyObject) {
let y: String = "uid=1";
let res = globalClass.sendInfo("http://www.myaddress.com/web-service/iostest.aspx", data: y);
let alert = UIAlertController(title: "", message: "", preferredStyle: .Alert);
let OK = UIAlertAction(title: "OK", style: .Default, handler: nil);
alert.addAction(OK);
if (res.errorCode==0) {
alert.title = "Info";
alert.message = res.answer;
} else if (res.errorCode==1) {
alert.title = "Error";
alert.message = "Error connecting to server";
} else {
alert.title = "Error";
alert.message = "Server returned an error";
}
dispatch_async(dispatch_get_main_queue()){
self.presentViewController(alert, animated: true, completion: nil);
};
}
感谢您的帮助,
阿夫欣·莫巴延·基亚巴尼
最佳答案
globalClass.sendInfo
使用异步调用 - dataTaskWithRequest
。请求的结果将在此方法完成时传递。但是您不会等待那个结果,而是尝试像同步函数一样使用 sendInfo
。
为了能够传递 dataTaskWithRequest
的完成结果,将您自己的完成放入 sendInfo
并在传递结果时调用此完成(闭包)。一个例子
struct GlobalClass {
static func sendInfo(url: String, data: String, completion: (answer: String?, errorCode: Int32?) -> Void) {
// you code here which prepares request
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
// you parse the result here
// you deliver the result using closure
completion(string, error)
}
task.resume();
}
}
以及一个使用示例:
func usage() {
GlobalClass.sendInfo("url", data: "data") { (answer, errorCode) in
// your answer and errorCode here
// handle the result
}
}
关于ios - 在其他与网络服务一起使用的 swift 文件中调用函数不返回任何内容,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38151632/