swift - 按值对 Swift 字典数组进行排序

Question

按值对 [String : String] 数组进行排序的最佳和最有效的方法是什么？

例如，

let dicts = [["key": "4"], ["key": "4"], ["key": "3"], ["key":"1"]]

然后在排序之后我想要

dicts = [["key": "1"], ["key": "3"], ["key": "4"], ["key":"4"]]

Answer 1

它有点罗嗦，但它可以让您很好地控制丢失的键和非 int 值。

var array = [["key": "1"], ["key": "3"], ["key": "2"], ["key":"4"]]
array.sort { (lhs, rhs) -> Bool in
    if let leftValue = lhs["key"], let leftInt = Int(leftValue), let rightValue = rhs["key"], let rightInt = Int(rightValue) {
        return leftInt < rightInt
    } else {
        return false // NOTE: you will need to decide how to handle missing keys and non-int values.
    }
}

如果您对比较更灵活一点并且想要更干净一点的东西。

array.sort {
    guard let leftValue = $0["key"], let rightValue = $1["key"] else {
        return false // NOTE: you will need to decide how to handle missing keys.
    }

    return leftValue.localizedStandardCompare(rightValue) == .orderedAscending
}